当我尝试测试rest-api不能正常工作时，邮递员中的所有方法都无法找到

debugcn 发表于 Dev

测试

型号类别

@Entity
public class Person {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long id;

@Column
public String name;

@Column
public String lastName;

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public String getLastName() {
    return lastName;
}

public void setLastName(String lastName) {
    this.lastName = lastName;
}

public Long getId() {
    return id;
}

}

-资料库

public interface PersonRepository extends JpaRepository<Person, Long>{
}

- 服务

public interface PersonServices {

Person addPerson(Person person);

Person findOne(Long id);

List<Person> findAll();
}

-实现服务接口的类

@Service
@Transactional
public class PersonServiesImpl implements PersonServices {

@Autowired
private PersonRepository personRepository;



@Override
@Transactional
public Person addPerson(Person person) {

    return personRepository.save(person);
}

@Override
@Transactional(readOnly=true)
public Person findOne(Long id) {
    return personRepository.findOne(id);
}

@Override

public List<Person> findAll() {
    // TODO Auto-generated method stub
    return personRepository.findAll();
}
}

控制器类

@RestController
@RequestMapping("/rest")
public class PersonController {

@Autowired
private PersonServices personServices;



@RequestMapping(value = "/user",
        method = RequestMethod.POST)
public ResponseEntity<Person> savePerson(@RequestBody Person person){
    return new ResponseEntity<Person>(personServices.addPerson(person),HttpStatus.CREATED);
}

@RequestMapping(value = "/user",
        method = RequestMethod.GET)
public ResponseEntity<List<Person>> findAll(){
    return new ResponseEntity<List<Person>>(personServices.findAll(),HttpStatus.OK);
}

@RequestMapping(value = "/user/{id}",
                method = RequestMethod.GET,
                produces = MediaType.APPLICATION_JSON_VALUE)
public ResponseEntity<Person> getFromId(@PathVariable("id")Long id){
    return new ResponseEntity<Person>(personServices.findOne(id),HttpStatus.OK);
}

}

--application.properties文件

 spring.datasource.url =jdbc:mysql://localhost:3306/managementsystem
 spring.datasource.username = root
 spring.datasource.password = root
 spring.datasource.driver-class-name=com.mysql.jdbc.Driver
 spring.jpa.database-platform=org.hibernate.dialect.MySQL5Dialect
 spring.jpa.hibernate.ddl-auto=update
 spring.profiles.active=dev
 server.port=8080
 server.sessionTimeout=30
 spring.jpa.hibernate.ddl-auto=create-drop
 tomcat.accessLogEnabled=false
 tomcat.protocolHeader=x-forwarded-proto
 tomcat.remoteIpHeader=x-forwarded-for
 tomcat.backgroundProcessorDelay=30

问题是，当我测试例如在数据库中保存一个人的方法时，邮递员返回的消息是{timestamp：1242424，message：找不到，path：/ rest / user。谁能帮我，我是Spring Boot Framework的初学者如何解决此问题？我检查了一些教程，但几乎不知道这样。我希望有人可以帮助我:)

幼稚的S

似乎未扫描RestController以及因此未扫描controller方法。您应该将Starter类（用@SpringBootApplication注释的类）放在文件夹层次结构中的控制器上方。

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