无法理解这段C ++代码

(rndseq[k] << 8) | (rand() & 0xff)

这些是二进制运算，（请参阅C中的位运算）

可以翻译成

rndseq[k] * 256 + rand() % 256

代码背后的想法是，创建一个带有随机条目的大数组，但是它的方法太复杂了

我希望这可以帮助您了解逻辑

    //we want to fill this array with random numbers
    static unsigned int rndseq[2048];
    // for each k-entry of the array
    for (k = 0; k < 2048; k++)
    {
                // initialize k-entry with zero
                rndseq[k] = 0;
                // for each byte in the k-entry integer
                for (i=0; i < (int)sizeof(int); ++i)
                    //on the first iteration rndseq[k] is zero, so  
                    //(rndseq[k] << 8) remains zero. 
                    //(rand() & 0xff) creates a random number in the range [0,255]
                    //-> in the first iteration rndseq[k] will be set to a random number ([0,255])
                    //lets say, you have a int32 (4 bytes)
                    //you need 1 byte to represent 255
                    //so you have 3 "empty" bytes and 1 filled
                    //lets say, rand() got the number 1
                    //than rndseq would have the following value
                    //0x00-0x00-0x00-0x01

                    //in the next iteration you shift 1 byte, so 
                    //you get from (rndseq[k] << 8)
                    //0x00-0x00-0x01-0x00
                    //the next random-number (still 1 byte) (lets say 2)
                    //will be stored in now free last byte
                    //result:
                    //0x00-0x00-0x01-0x02
                    //now you repeat, until all bytes are set
                    //result:
                    //0x01-0x02-0x03-0x04
                    rndseq[k] = (rndseq[k] << 8) | (rand() & 0xff);
    }