我有这样的数据框
A B
0 1 a
1 2 a
2 3 b
3 4 b
4 5 a
我想得到下面的结果（1行* 4列数据框），
A_count_all means the number of rows in dataframe df.A.count()
A_sum_all means the df.A.sum()
A_count_a is df.loc[df.B==a,"A"].count()
A_sum_a is df.loc[df.B==a,"A"].sum()
A_count_all A_sum_all A_count_a A_sum_a
0 5 15 3 8
如何获得此结果数据框？
您可以使用DataFrame构造函数：
A_count_all = df.A.count()
A_sum_all = df.A.sum()
A_count_a = df.loc[df.B=='a',"A"].count()
A_sum_a = df.loc[df.B=='a',"A"].sum()
print (pd.DataFrame({'A_count_all':A_count_all,
'A_sum_all':A_sum_all,
'A_count_a':A_count_a,
'A_sum_a':A_sum_a},
index=[0],
columns=['A_count_all','A_sum_all','A_count_a','A_sum_a']))
A_count_all A_sum_all A_count_a A_sum_a
0 5 15 3 8
感谢您Kris提供另一种解决方案：
print (pd.DataFrame(data=[[df.A.count(),
df.A.sum(),
df.loc[df.B=='a',"A"].count(),
df.loc[df.B=='a',"A"].sum()]],
columns=['A_count_all','A_sum_all','A_count_a','A_sum_a']))
A_count_all A_sum_all A_count_a A_sum_a
0 5 15 3 8
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