Python初学者在这里。
我有一个目录，其中包含成百上千个名为（按顺序）的图像文件：
002_IMG_001、002_IMG_002、002_IMG_003、002_IMG_N
现在，我正在尝试重命名这些图像，以使连续的五个文件从1：5开始具有“ N”，也就是说，每五个连续的图像集都将N从1变为5。我也想粘贴另一个字符串在数字“ N”之前。此字符串将跟踪N个图像集，例如IMG_001_1，IMG_001_2，.. IMG_001_N，IMG_002_1，IMG_002_2，... IMG_00X_N。
在Mac上的python 2.7.10上的伪代码如下所示：
import os
myDir = "/Users/path/to/dir/"
fileList = os.listdir(myDir)
for filename in fileList :
#split the images into sets of five each
newFile = 'IMG_' + '00' + X + '_' + N
#loop through images and rename
os.rename(fileName, newFile)
我想我需要for循环内部的条件，例如：
if int(filename[9:12]) % 5 == 0
但这意味着，我必须为1到5创建五个单独的条件，这似乎不正确。任何提示将不胜感激？
编辑：尚不清楚需要什么类型的输出。我正在寻找一个函数来获取最终文件名，例如：IMG_001_1，IMG_001_2，... IMG_001_5，IMG_002_1，IMG_002_2，... IMG_002_5，...
我认为这应该工作：
my_list = ["002_IMG_001", "002_IMG_002", "002_IMG_003", "002_IMG_004", "002_IMG_005",
"002_IMG_006", "002_IMG_007", "002_IMG_008", "002_IMG_009", "002_IMG_0010",
"002_IMG_011", "002_IMG_012", "002_IMG_013", "002_IMG_014", "002_IMG_015",
"002_IMG_016", "002_IMG_017", "002_IMG_018", "002_IMG_019", "002_IMG_0020",
]
fileList.sort()
print("Original list:\n")
print(fileList)
new_list = []
for index, old_file_name in enumerate(fileList):
group, subgroup = divmod(index,5)
group, subgroup = group + 1, subgroup + 1
new_file_name = "IMG_{0:03d}_{1}".format(group, subgroup)
new_list.append(new_file_name)
os.rename(old_file_name, new_file_name)
print("\nNew list:\n")
print (new_list)
这是输出：
Original list:
['002_IMG_001', '002_IMG_002', '002_IMG_003', '002_IMG_004', '002_IMG_005',
'002_IMG_006', '002_IMG_007', '002_IMG_008', '002_IMG_009', '002_IMG_0010',
'002_IMG_011', '002_IMG_012', '002_IMG_013', '002_IMG_014', '002_IMG_015',
'002_IMG_016', '002_IMG_017', '002_IMG_018', '002_IMG_019', '002_IMG_0020']
New list:
['IMG_001_1', 'IMG_001_2', 'IMG_001_3', 'IMG_001_4', 'IMG_001_5',
'IMG_002_1', 'IMG_002_2', 'IMG_002_3', 'IMG_002_4', 'IMG_002_5',
'IMG_003_1', 'IMG_003_2', 'IMG_003_3', 'IMG_003_4', 'IMG_003_5',
'IMG_004_1', 'IMG_004_2', 'IMG_004_3', 'IMG_004_4', 'IMG_004_5']
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