无法将Powershell中的变量从函数传递到脚本

debugcn 发表于 Dev

丹·史蒂文森

这是我遇到麻烦的代码部分：


function getGroup {
$Script:confirmdggroup = "N"
$Script:dggroup = "none"
$dggroup = Read-Host -Prompt 'Enter the name of the group to add a member'
write-host "You entered $dggroup"
$confirmdggroup = Read-Host -Prompt 'If the group name is correct enter Y'
write-host "You entered $confirmdggroup when asked to confirm group name"
}

If ($confirmdggroup -ne "Y") {getGroup}
write-host "Group name to be modified is $dggroup"
write-host "the confirmdggroup variable is: $confirmdggroup"

这是我运行它时输入和输出的图像。您可以看到变量是在函数内部正确分配的，而不是在函数外部正确分配的。我究竟做错了什么？

好的，我正在尝试重写并且不使用“脚本：”，但是我无法获取该函数以返回任何内容。这是新功能：


function getGroup {
while($confirmDGGroup -ne "Y")
  {
    $DGGroup = Read-Host -Prompt 'Enter the name of the Exchange group to modify'
    ""
    write-host "You entered $DGGroup"
    ""
    $confirmDGGroup = Read-Host -Prompt 'If the group name is correct enter Y'
  }
}

cls
write-host "This script will add or remove email addresses from an Exchange Distibution Group"
""
$GroupName = getGroup
write-host "The get group function returned $GroupName"
pause

这是我现在得到的输出：

此脚本将从Exchange分发组中添加或删除电子邮件地址

输入要修改的Exchange组的名称：office
您输入的office
如果组名正确，请输入Y：Y
返回“获取组”功能  
按Enter继续...：

李·戴利

此功能可获取用户输入，询问是否正确，如果不正确则重复该操作，最后将文本发送给调用方。

function Get-ExchangeGroupName
    {
    $Prompt = 'Please enter the Group name '

    $Choice = ''
    while ($Choice -eq '')
        {
        $Choice = Read-Host $Prompt
        Write-Host ('You entered [ {0} ].' -f $Choice)
        $YesNo = Read-Host '    Is that correct? [n/y]'
        if ($YesNo -eq 'y')
            {
            # send the result out to the caller
            $Choice
            }
            else
            {
            $Choice = ''
            }
        }
    } # function Get-ExchangeGroupName

$ChosenGroupName = Get-ExchangeGroupName
''
$ChosenGroupName

输出带有n＆的y“正确吗？”响应 ...

Please enter the Group name : qwerty
You entered [ qwerty ].
    Is that correct? [n/y]: n
Please enter the Group name : AlfaBravo
You entered [ AlfaBravo ].
    Is that correct? [n/y]: y

AlfaBravo

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