我正在尝试找出如何传递itertools.product动态数量的参数。
我有以下代码,可以按预期方式打印出行,每行以不同的顺序包含4个字符:
#!/usr/bin/env python3.5
import sys, itertools, multiprocessing, functools
alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ12234567890!@#$%^&*?,()-=+[]/;"
num_parts = 4
part_size = len(alphabet) // num_parts
def do_job(first_bits):
for x in itertools.product(first_bits, alphabet, alphabet, alphabet):
print(''.join(x))
if __name__ == '__main__':
pool = multiprocessing.Pool(processes=4)
results = []
for i in range(num_parts):
if i == num_parts - 1:
first_bit = alphabet[part_size * i :]
else:
first_bit = alphabet[part_size * i : part_size * (i+1)]
pool.apply_async(do_job, (first_bit,))
pool.close()
pool.join()
然后,我尝试使用以下代码使其完全动态,其中基于num_parts变量动态创建字母参数的数量:
#!/usr/bin/env python3.5
import sys, itertools, multiprocessing, functools
alphabet = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ12234567890!@#$%^&*?,()-=+[]/;"
num_parts = 4
part_size = len(alphabet) // num_parts
dynamicArgs = []
def do_job(first_bits):
for x in itertools.product(first_bits, *dynamicArgs):
print(''.join(x))
if __name__ == '__main__':
pool = multiprocessing.Pool(processes=4)
results = []
for x in range(num_parts-1):
dynamicArgs.append(alphabet)
for i in range(num_parts):
if i == num_parts - 1:
first_bit = alphabet[part_size * i :]
else:
first_bit = alphabet[part_size * i : part_size * (i+1)]
pool.apply_async(do_job, (first_bit,))
pool.close()
pool.join()
但这不能按预期方式工作……它输出每行只有一个字符的行,并且仅在字母表上进行一次迭代。
如何将动态数量的字母变量作为参数传递给itertools.product?
谢谢你的时间。
您可以只将字符串列表相乘:
def do_job(first_bits):
for x in itertools.product(first_bits, *[alphabet] * 3):
您还可以使用itertools.repeat:
from itertools import repeat
def do_job(first_bits, times):
for x in itertools.product(first_bits, *repeat(alphabet, times)):
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我来说两句