我已经知道如何放入h4 h7 h8 h9 h7一个以空格作为定界符的数组，但是在那之后，我试图h将数字与数字分开以将数字相互比较。
如何在bash脚本中拆分这些内容？
#!/bin/bash
arr=( h4 h7 h8 h9 h7 )
for thing in "${arr[@]}"; do
num=${thing#?}
printf 'The number in "%s" is %d\n' "$thing" "$num"
done
变量扩展从中${variable#pattern}删除匹配的最短前缀字符串。模式匹配单个字符。pattern$variable?
输出将是
The number in "h4" is 4
The number in "h7" is 7
The number in "h8" is 8
The number in "h9" is 9
The number in "h7" is 7
或者，要忽略非数字前缀，不管它有多长，请使用sed，
#!/bin/bash
arr=( hello4 happy7 hobbit8 hulk9 hr-department7 )
for thing in "${arr[@]}"; do
num=$( printf '%s\n' "$thing" | sed 's/^[^[:digit:]]*//' )
printf 'The number in "%s" is %d\n' "$thing" "$num"
done
或者，使用末尾数字的正则表达式匹配，
#!/bin/bash
arr=( hello4 happy7 hobbit8 hulk9 hr-department7 )
for thing in "${arr[@]}"; do
if [[ "$thing" =~ ([[:digit:]]+)$ ]]; then
printf 'The number in "%s" is %d\n' "$thing" "${BASH_REMATCH[1]}"
fi
done
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