句子中单词的位置无法正常工作

debugcn 发表于 Dev

强尼

我的代码有问题：

def sentence_recreation(grammar_choice, sentence):
    new_sentence=''
    for char in sentence:
        if char not in grammar_choice:
            new_sentence=new_sentence + char
            sentence_list=new_sentence.split()
    compression(sentence_list)

def validation(sentence):
    if sentence=='':
        print('Input invalid. Please enter a sentence: ')
        compress_sentence()
    else:
        grammar_choice = input("Would you like to remove any punctuation or numbers in your sentence?('None', 'Both', 'Punctuation' or 'Numbers'): ")
        grammar_choice.lower()
        both=('''!()-[]{};:'"\,<>./?@#$%^&*_~0123456789''')
        punctuation=('''!()-[]{};:'"\,<>./?@#$%^&*_~''')
        numbers=('0123456789')
        #These if statements decide to remove: nothing, punctuation, numbers or punctuation and numbers
        if grammar_choice=='':
            print('Input invalid. Please try again.')
            validation(sentence)
        if grammar_choice=="none":
            sentence_list=sentence.split()
            compression(sentence_list)
        elif grammar_choice == "punctuation":
            grammar_choice = punctuation
            sentence_recreation(grammar_choice, sentence)
        elif grammar_choice == "numbers":
            grammar_choice = numbers
            sentence_recreation(grammar_choice, sentence)
        elif grammar_choice == "both":
            grammar_choice = both
            sentence_recreation(grammar_choice, sentence)
        else:
            print('Input invalid. Please try again.')
            validation(sentence)

def compression(sentence_list):
    words=[]
    positions=[]
    y={}
    #This enumerate function allows the program to create two lists with the unique words as well as the positions of those words within the sentence
    for i,x in enumerate(sentence_list):
        if x in y:
            positions.append(y[x])
        else:
            y[x]=i
            positions.append(i)
    for i,x in enumerate(sentence_list):
        if sentence_list[i] not in words:
            words.append(sentence_list[i])
    print(words)
    print(positions)
    file=open('positions and words.txt','w')
    file.write(str(words))
    file.write(str(positions))
    file.close
    print('Goodbye')
    import sys
    sys.exit()

def compress_sentence():
    sentence=input('Please enter your desired sentence: ')
    validation(sentence)

compress_sentence()

当输出句子中单词的位置时，由于某些原因，该代码似乎不起作用，因此代码可以工作到一定程度，例如：

>>> 
Please enter your desired sentence: When you crack the code, you don't just crack the code, you crack all the codes 1.048596
Would you like to remove any punctuation or numbers in your sentence?('None', 'Both', 'Punctuation' or 'Numbers'): none
['When', 'you', 'crack', 'the', 'code,', "don't", 'just', 'all', 'codes', '1.048596']
[0, 1, 2, 3, 4, 1, 6, 7, 2, 3, 4, 1, 2, 13, 3, 15, 16]
Goodbye
>>>

该程序应该输出位置[0,1,2,3,4,1,5,6,2,3,4,1,2,7,3,8,9]，但是不会。我真的很感谢您的帮助，因为我不确定要解决的问题，也不清楚为什么要这样做。

克里斯

这是您问题的根源：

positions.append(i)

这是从枚举函数中附加索引，该索引是附加每个唯一单词的原始位置，因此数量不断增加。您想要做的是为每个新术语增加一个增量。可以通过将该行更改为以下内容来实现：

positions.append(len(y) -1)

输出：

Please enter your desired sentence:  When you crack the code, you don't just crack the code, you crack all the codes 1.048596
Would you like to remove any punctuation or numbers in your sentence?('None', 'Both', 'Punctuation' or 'Numbers'):  none
['When', 'you', 'crack', 'the', 'code,', "don't", 'just', 'all', 'codes', '1.048596']
[0, 1, 2, 3, 4, 1, 5, 6, 2, 3, 4, 1, 2, 7, 3, 8, 9]
Goodbye

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