我正在为我的应用程序使用quickblox。此应用程序均适用于android iOS。我正在处理推送通知。为此，我使用以下代码：
// Send push to users with ids 292,300,1295
QBMEvent *event = [QBMEvent event];
event.notificationType = QBMNotificationTypePush;
event.usersIDs = [NSString stringWithFormat:@"%ld", (long)recepID];
event.type = QBMEventTypeOneShot;
// standart parameters
// read more about parameters formation http://quickblox.com/developers/Messages#Use_custom_parameters
//
NSMutableDictionary *dictPush = [NSMutableDictionary dictionary];
[dictPush setObject:@"Message received from Bob" forKey:@"message"];
[dictPush setObject:@"5" forKey:@"ios_badge"];
[dictPush setObject:@"mysound.wav" forKey:@"ios_sound"];
// custom params
[dictPush setObject:@"234" forKey:@"user_id"];
[dictPush setObject:@"144" forKey:@"thread_id"];
NSError *error = nil;
NSData *sendData = [NSJSONSerialization dataWithJSONObject:dictPush options:NSJSONWritingPrettyPrinted error:&error];
NSString *jsonString = [[NSString alloc] initWithData:sendData encoding:NSUTF8StringEncoding];
//
event.message = jsonString;
[QBRequest createEvent:event successBlock:^(QBResponse * _Nonnull response, NSArray<QBMEvent *> * _Nullable events)
{
// Successful response with event
NSLog(@"Create event successfully to: %ld", (long)recepID);
}
errorBlock:^(QBResponse * _Nonnull response)
{
// Handle error
NSLog(@"Create event error to: %@", response.error.description);
}];
此创建事件失败，并且显示此错误：
Create event error to:
Error reasons:{
errors = (
"No one can receive the message"
);
}
所有设备都在“订阅”部分中。仍然会给出错误。我从这个quickblox文档中复制了此代码。请帮我。
通过在我的代码中添加以下行来解决此问题：
event.isDevelopmentEnvironment = ![QBApplication sharedApplication].productionEnvironmentForPushesEnabled;
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我来说两句