如何在tkinter和python中刷新标签

debugcn 发表于 Dev

请帮帮我

我正在尝试创建一个小窗口，以告诉我前十名玩家的资金状况。问题是，每当我按下“更新”按钮时，它都不会删除播放器标签的旧列表。tkinter中有明确的功能吗？

代码：

from tkinter import *
import sqlite3
def getlist():

    conn = sqlite3.connect('C:\sqlite\crapsdatabase.db')
    c = conn.cursor()

    c.execute("SELECT playerName, playerBank FROM player ORDER BY playerBank desc limit 10")
    temp = c.fetchall()
    for row in temp:
        texthold = str(row[0]) + ' ' + str(row[1])
        print(texthold)
        player = Label(root, text=texthold)
        player.pack()


    conn.commit() #confirms changes to the databae
    c.close() #closes the connection to the database
    conn.close()

root =Tk()

theLabel =Label(root, text="Top Ten Players")



buttonUpdate = Button(root, text="Update", fg="green", command = getlist)
buttonUpdate.pack()

theLabel.pack()
root.mainloop()

法尔扎德

由于getlist()正在Label为每个项目创建一个新列表，因此一种方法是从窗口（和内存）中删除以前的列表，并生成一个新的播放器列表（和标签）。

我们需要保留对创建的标签的引用（在中getlist()），以便稍后将其删除。类似于以下代码（尝试更改为所讨论代码示例的最小值）：

from tkinter import *
import sqlite3

top_list = [] # holds the player labels currently shown

def getlist():
    global top_list

    conn = sqlite3.connect('C:\sqlite\crapsdatabase.db')
    c = conn.cursor()    
    c.execute("SELECT playerName, playerBank FROM player ORDER BY playerBank desc limit 10")
    temp = c.fetchall()

    for player in top_list:
        player.pack_forget() # remove label from window
    top_list = [] # remove references to free memory

    for row in temp:
        texthold = str(row[0]) + ' ' + str(row[1])
        print(texthold)
        player = Label(root, text=texthold)
        player.pack()
        top_list.append(player)

    conn.commit() #confirms changes to the databae
    c.close() #closes the connection to the database
    conn.close()

root = Tk()

theLabel = Label(root, text="Top Ten Players")
buttonUpdate = Button(root, text="Update", fg="green", command=getlist)
buttonUpdate.pack()

theLabel.pack()
root.mainloop()

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