如何将2个数组合并为一个数组？

debugcn 发表于 Dev

波斯菊

我有2个数组，正如您将在下面看到的，我希望将主题组合成一个数组。前两个数组具有子数组，它们的总和为一个月。结果array（3rd）必须具有同一月份的前2个数组的总和。

array:3 [
  0 => array:2 [
    "sum" => 179.0
    "month" => "2016-01"
  ]
  1 => array:2 [
    "sum" => 34.0
    "month" => "2016-02"
  ]
  2 => array:2 [
    "sum" => 67.0
    "month" => "2016-03"
  ]
]


array:2 [
  0 => array:2 [
    "sum" => 143.25
    "month" => "2016-01"
  ]
  1 => array:2 [
    "sum" => 479.0
    "month" => "2016-03"
  ]
]


Total:

array:3 [
  0 => array:3 [
    "sum" => 313.25
    "month" => "2016-01"
  ]
  1 => array:2 [
    "sum" => 34.0
    "month" => "2016-02"
  ]
  2 => array:2 [
    "sum" => 546.0
    "month" => "2016-03"
  ]
]

我试过的

for($i=0;$i<count($com1);$i++){
            for ($j=0; $j < count($com2); $j++) { 
                if($com1[$i]['month'] == $com2[$j]['month']){
                    $total = $com1[$i]['sum']+$com2[$j]['sum']
                }
            }
        }

但这并没有给我想要的结果

我有点菜鸟...希望有人能提供帮助。谢谢

布雷维斯

尝试这个：

$com1 = [
  0 => [
    'sum' => 179.0,
    'month' => '2016-01'
  ],
  1 => [
    'sum' => 34.0,
    'month' => '2016-02'
  ],
  2 => [
    'sum' => 67.0,
    'month' => '2016-03'
  ]
];

$com2 = [
  0 => [
    'sum' => 143.25,
    'month' => '2016-01'
  ],
  1 => [
    'sum' => 479.0,
    'month' => '2016-03'
  ]
];

$total = [];
foreach ($com1 as $data) {
    $total[$data['month']] = $data;
}

foreach ($com2 as $data) {
    if (!isset($total[$data['month']])) {
        $total[$data['month']] = [
            'sum' => 0,
            'month' => $data['month']
        ];
    }
    $total[$data['month']]['sum'] += $data['sum'];
}

print_r($total);

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