我最近一直在玩脚本..在@Cas的帮助下写了这个
#!/bin/bash
## Variables ##
host="`/bin/hostname`";
## Limits ##
OneMin="1";
FiveMin="6";
FifteenMin="6";
## Mail IDs ##
To="[email protected], [email protected]";
Fr="root@"$host;
## Load Averages ##
LA=(`uptime | grep -Eo '[0-9]+\.[0-9]+' | cut -d"." -f1`)
## Top Process List ##
tp=(`ps -ef | sort -nrk 3,3 | grep -E "(php|httpd)" | grep -v root | head -n30 | awk '{print $2}'`)
## Actions ##
if [ ${LA[0]} -ge $OneMin ]; then
## Send Mail ##
echo -e "From: $Fr
To: $To
Subject: *ALERT* - Current Load on '$host' Is High
Load Averages Are: \n\n
1:Min\t5:Min\t15:Min \n
${LA[0]}\t${LA[1]}\t${LA[2]} \n\n
List Of Processes That Were Killed \n" | sendmail -t
## Kill Top Pocesses ##
for i in $tp ; do
kill -9 $i
done
fi
我不确定该数组是否有效，尤其是最后一部分，我在其中添加了一个循环以杀死顶级进程。.因为它不打印该电子邮件中的进程列表。我不知道为什么。但是脚本不会给出任何错误。
OK ##替代方法##
顺便说一句，这行得通吗？
#!/bin/bash
## Variables ##
host="`/bin/hostname`";
## Limits ##
OneMin="7";
FiveMin="6";
FifteenMin="6";
## Load Averages ##
LA=(`uptime | grep -Eo '[0-9]+\.[0-9]+' | cut -d"." -f1`)
## Actions ##
## One Minut Action ##
if [ ${LA[0]} -ge $OneMin ]; then
## Send Mail ##
echo -e "From: $Fr
To: $To
Subject: *ALERT* - Current Load on '$host' Is High
Load Averages Are: \n\n
1:Min\t5:Min\t15:Min \n
${LA[0]}\t${LA[1]}\t${LA[2]} \n\n
List Of Processes That Were Killed \n
`ps -ef | sort -nrk 3,3 | grep -E "(php|httpd)" | grep -v root | head -n30 | awk '{print $2}'`" | sendmail -t
## Kill Top Pocesses ##
for i in `ps -ef | sort -nrk 3,3 | grep -E "(php|httpd)" | grep -v root | head -n30 | awk '{print $2}'` ; do
kill -9 $i
done
fi
我的意思是这会杀死所有的PiD吗？
问题在于，它tp=(...定义了一个数组，但仅$tp引用该数组的第一个元素。
你需要
for i in "${tp[@]}" ; do
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我来说两句