我想将double值存储到Array中，然后合并以计算一些结果，但是遇到了一些错误。还有另一种方法吗？
NSMutableArray *storeImpedance;
NSMutableArray *storeLength;
double designFrequency = 1e9;
double simulateFrequency = 1.5e9;
double pi = 3.14159265359;
double omega = 2*pi*simulateFrequency;
double Z0=50;
- (void)viewDidLoad {
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
storeImpedance = [[NSMutableArray alloc]initWithCapacity:25];
storeLength = [[NSMutableArray alloc]initWithCapacity:25];
}
- (IBAction)addButton:(UIButton *)sender {
storeCount++;
[storeImpedance addObject:[NSNumber numberWithDouble:[impedanceTextField.text doubleValue]]];
[storeLength addObject:[NSNumber numberWithDouble:[lengthTextField.text doubleValue]]];
}
if (imageIndex==1)
{
thetarad=storeImpedance*pi/180*simulateFrequency/designFrequency;
A=cos(thetarad);
B=I* storeImpedance*sin(thetarad);
C=I*sin(thetarad)/storeImpedance;
D=cos(thetarad);
}
在这一行：
hetarad=storeImpedance*pi/180*simulateFrequency/designFrequency;
您正在使用storeImpedance这类型的NSMutableArray，在这种表达式的预期类型double。
double从数组中提取所需的值，并使用它来解决问题：
NSNumber *number = (NSNumber *)[storeImpedance firstObject]; // Or use objectAtIndex: for a specific value in the array if it is not the first one
double value = [number doubleValue];
hetarad=value*pi/180*simulateFrequency/designFrequency;
如果要计算hetarad数组中的每个值：
for (id element in storeImpedance) {
NSNumber *number = (NSNumber *)element
double value = [number doubleValue];
hetarad=value*pi/180*simulateFrequency/designFrequency;
// You should do something with hetarad here (either store it or use in other required logic otherwise it will be overwritten by the next iteration
}
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