选择查询偶数和奇数计数

debugcn 发表于 Dev

阿卜杜贾里尔·楚利夫

仅当Image_ID1和Image_ID2不是时，这些方法才会给出结果null。如果其中一个或两个都为空，则显示错误。除了仅返回偶数计数外，还将跳过奇数计数。示例，列Image_ID1=1,3,null和Image_ID2=2,4,6。它必须显示1,2,3,4,6值，但显示1,2,3,4导致该null值的值。我该如何解决这些问题？

private void BindGrid()
    {
        MySqlConnection con = new MySqlConnection(constr);
        MySqlCommand cmd = new MySqlCommand("SELECT * FROM images where Image_ID in (" + String.Join(",", getImage_ID()) + ")", con);
        MySqlDataAdapter da = new MySqlDataAdapter(cmd);
        DataTable dt = new DataTable();
        da.Fill(dt);
        gvImages.DataSource = dt;
        gvImages.DataBind();
    }
    private List<int> getImage_ID()
    {
        List<int> i = new List<int>();
        MySqlConnection con = new MySqlConnection(constr);
        con.Open();
        string query = "Select Image_ID1, Image_ID2 from register where students_ID='" + getStudents_ID() + "'AND Image_ID1 IS NOT NULL AND Image_ID2 IS NOT NULL"; 
        MySqlCommand cmd = new MySqlCommand(query);
        cmd.Connection = con;
        MySqlDataReader reader = cmd.ExecuteReader();
        foreach (DbDataRecord s in reader)
            {
                i.Add(s.GetInt32(0));
                i.Add(s.GetInt32(1));
            }
        return i;
    }

蒂姆·施密特（Tim Schmelter）

我建议使用一个查询/方法：

string sql = @"
    SELECT img.* FROM
    (
        SELECT i.* FROM Images i
        INNER JOIN  register r
          ON i.Image_ID = r.Image_ID1
        WHERE r.students_ID = @studentsID

        UNION ALL

        SELECT i.* FROM Images i
        INNER JOIN  register r
          ON i.Image_ID = r.Image_ID2
        WHERE r.students_ID = @studentsID
    ) img
";

MySqlCommand cmd = new MySqlCommand(sql , con);
cmd.Parameters.Add("@studentsID", MySqlDbType.Int32).Value = getStudents_ID();
MySqlDataAdapter da = new MySqlDataAdapter(cmd);
DataTable dt = new DataTable();
da.Fill(dt);

本文收集自互联网，转载请注明来源。

如有侵权，请联系[email protected] 删除。