未知列where子句（MySQL）

我有这个MySQL查询。但是，我想知道为什么会收到此错误消息。

“ where子句”中的未知列“ min_pp_distance”

我很确定我在查询中有此变量。

 IF(PP.latitude <> 0 AND PP.longitude <> 0, ( 6371 * acos( cos( radians(3.5951956) ) * cos( radians( PP.latitude ) ) * cos( radians( PP.longitude ) - radians(98.6722227) ) + sin( radians(3.5951956) ) * sin( radians( PP.latitude ) ) ) ) , 9999999) as min_pp_distance

这是完整的查询（我整理并删除了一些不必要的变量）

SELECT SQL_CALC_FOUND_ROWS D.id * -1 as id, D.doc_title as doc_title, 
NULL as user_email, D.first_name, D.last_name,

...
CONCAT_WS('#', PP.id, PP.name) as pp_name, CONCAT_WS('#', PP.id, PP.address) 
as pp_address, CONCAT_WS('#', PP.id, PP.phone) as pp_phone, CONCAT_WS('#', 
PP.id, V.name)as pp_vil, CONCAT_WS('#', PP.id, SD.name) as pp_sub_d, 
CONCAT_WS('#', PP.id, C.name) as pp_city, CONCAT_WS('#', PP.id, P.name) as 
pp_province, CONCAT_WS('#', PP.id, PP.zipcode) as pp_zip, 1 pp_is_primary, 
CONCAT_WS('#', PP.id, PP.latitude) as pp_lat, CONCAT_WS('#', PP.id, 
PP.longitude) as pp_lng, CONCAT_WS('#', PP.id, PP.type) as pp_type, 
CONCAT_WS('#', PP.id,

IF(PP.latitude <> 0 AND PP.longitude <> 0, ( 6371 * 
acos( cos( radians(3.5951956) ) * cos( radians( PP.latitude ) ) * cos( 
radians( PP.longitude ) - radians(98.6722227) ) + sin( radians(3.5951956) ) 
* sin( radians( PP.latitude ) ) ) ), 0)) as pp_distance, IF(PP.latitude <> 0 AND PP.longitude <> 0, ( 6371 * acos( cos( radians(3.5951956) ) * cos(radians( PP.latitude ) ) * cos( radians( PP.longitude ) - 
radians(98.6722227) ) + sin( radians(3.5951956) ) * sin( radians( 
PP.latitude ) ) ) ) , 9999999) as min_pp_distance,

....
 D.status as reg_status FROM register_doctor D LEFT JOIN 
 ref_doctor_practice_place RDPP ON RDPP.doctor_id = D.id * -1 LEFT JOIN 
 practice_place PP ON PP.id = RDPP.practice_place_id LEFT JOIN village V ON 
 V.id = PP.village_id LEFT JOIN sub_district SD ON SD.id =PP.sub_district_id 
 LEFT JOIN city C ON C.id = SD.city_id INNER JOIN province P ON P.id = 
 PP.province_id INNER JOIN city RDC ON RDC.id = D.city_id AND RDC.name LIKE 
 '%Medan%' INNER JOIN province RDP ON RDP.id = RDC.province_id AND ( RDP.name 
LIKE 'Sumatera Utara%' OR RDP.long_name LIKE 'Sumatera Utara%' ) INNER JOIN 
...
WHERE D.status = 2 AND min_pp_distance < 50 OR min_pp_distance = 9999999 GROUP BY D.id ORDER BY min_pp_distance ASC, RAND() LIMIT 0,10

这是创建表：

CREATE TABLE IF NOT EXISTS `register_doctor` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `doc_title` int(11) NOT NULL,
  `first_name` varchar(35) NOT NULL,
  `last_name` varchar(35) DEFAULT NULL,
  `gender` int(11) NOT NULL,
  `city_id` int(11) NOT NULL,
  `province_id` int(11) NOT NULL,
  `status` int(11) NOT NULL COMMENT '0 = Pending; 1 = Verified, 2 = Not Reg Yet, 3 = Pending Approval',
  `str_number` char(6) DEFAULT NULL,
  `editted_by` int(11) DEFAULT NULL,
  `editted_date` bigint(20) DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `city_id` (`city_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=179327 ;

CREATE TABLE IF NOT EXISTS `practice_place` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `name` varchar(75) NOT NULL,
  `statement` text,
  `address` varchar(200) NOT NULL,
  `phone` varchar(15) NOT NULL,
  `fax` varchar(15) NOT NULL,
  `email` varchar(50) NOT NULL,
  `village_id` varchar(50) NOT NULL,
  `sub_district_id` varchar(50) NOT NULL,
  `province_id` varchar(50) NOT NULL,
  `zipcode` varchar(10) NOT NULL,
  `website` varchar(50) NOT NULL,
  `latitude` double NOT NULL,
  `longitude` double NOT NULL,
  `type` int(11) NOT NULL,
  `managed_by` int(11) DEFAULT '0',
  `doctor_group_id` int(11) NOT NULL,
  `category` varchar(50) NOT NULL,
  `photo_file` char(36) NOT NULL,
  `is_branch` int(11) NOT NULL,
  `parent_id` int(11) NOT NULL,
  `editted_by` int(11) NOT NULL,
  `editted_date` bigint(20) NOT NULL,
  `status` int(11) NOT NULL,
  PRIMARY KEY (`id`),
  KEY `village_id` (`village_id`),
  KEY `doctor_group_id` (`doctor_group_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=25557 ;

CREATE TABLE IF NOT EXISTS `ref_doctor_practice_place` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `doctor_id` int(11) NOT NULL,
  `practice_place_id` int(11) NOT NULL,
  `is_primary` int(11) NOT NULL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `doctor_id_2` (`doctor_id`,`practice_place_id`),
  KEY `doctor_id` (`doctor_id`),
  KEY `practice_place_id` (`practice_place_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=38840 ;

有人看到我看不到的东西吗？