使用php以可编辑的html文本形式从数据库返回结果

debugcn 发表于 Dev

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EMP    |T_IN    |T_OUT    |ITEM    |NOTES
-----------------------------------------
Name 1 | time   | time    | break  | job1
Name 2 | time   | time    | break  | job2
Name 1 | time   | time    | office | 
Name 3 | time   | time    | fab    | job6

上面我需要每个行列交叉点中的每个项目都以可编辑的html文本框形式显示，以提交到下一步。香港专业教育学院尝试了几件事...我都放弃了。

<!DOCTYPE html>
<html>
<body>

<form action="test.php" method="post">
Pay Range 
  <input type="date" name="start">
<input type="date" name="stop">
  <input type="submit">
</form>

</body>
</html>


<?php
if($_POST){
mysql_connect('localhost', 'user', 'Pass');
mysql_select_db('database');
$rt = mysql_query("SELECT * FROM TIME WHERE STAMP BETWEEN '". $_POST['start']."' AND '".$_POST['stop']."'");



while($data = mysql_fetch_array($rt)){

    $results .= $data['EMP'].", ".$data['T_IN'].", ".$_POST['T_OUT'].", ".$_POST['ITEM'].", ".$_POST['NOTE'];
echo $results."<br/>";
}
}




?>

更新的代码：

<!DOCTYPE html>
<html>
<body>

<form action="test.php" method="post">
Pay Range 
  <input type="date" name="start">
<input type="date" name="stop">
  <input type="submit">
</form>

</body>
</html>

<?php
$servername = "localhost";
$username = "user";
$password = "Pass";
$dbname = "DB";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$sql = "SELECT * FROM TIME WHERE STAMP BETWEEN '". $_POST['start']."' AND '".$_POST['stop']."'";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()){
        echo "<input type="text" value=\"" . $row['EMP']. "\"> <br>";
    }
} else {
    echo "0 results";
}
$conn->close();
?>

托马斯·K

这将从您的MySQL查询中输出所有数据

    <?php
    $servername = "localhost";
    $username = "username";
    $password = "password";
    $dbname = "myDB";

    // Create connection
    $conn = new mysqli($servername, $username, $password, $dbname);
    // Check connection
    if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
    } 

    $sql = "SELECT id, firstname, lastname FROM MyGuests";
    $result = $conn->query($sql);?>
      <form action="test.php" method="post">
   <?php if ($result->num_rows > 0) {
        // output data of each row
        while($row = $result->fetch_assoc()){
    echo '<input type="text" name="myinput" value="' . $row["id"]. '"> <br>'
        }
    } else {
        echo "0 results";
    }
    $conn->close();
    ?>
       </form>

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