将Obj-C转换为Swift ep1

debugcn 发表于 Dev

芬迪

我希望您能将Obj-C转换为Swift，因为我对Obj-C不了解

viewController.h：

 #import <UIKit/UIKit.h>

#define kPostURL @"http://localhost/tutorialTest.php"
#define kName @"name"
#define kMessage @"message"

@interface ViewController : UIViewController{

IBOutlet UITextField *nameText;
IBOutlet UITextView *messageText;
NSURLConnection *postConnection;

}

-(IBAction)save:(id)sender;

@end

viewController.m：

 -(void) postMessage:(NSString*) message withName:(NSString *) name{

    if (name != nil && message !=nil){

        NSMutableString *postString = [NSMutableString stringWithString:kPostURL];

        [postString appendString:[NSString stringWithFormat:@"?%@=%@", kName, name]];

        [postString appendString:[NSString stringWithFormat:@"&%@=%@", kMessage, message]];

        [postString setString:[postString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];

        NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:postString]];
       [request setHTTPMethod:@"POST"];

        postConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self startImmediately:YES];

    }
}

我希望你们能帮助我翻译成Swift。谢谢

姆鲁纳尔

我想这可能会有所帮助。它的翻译不完全正确，但是您可以通过解决编译时和运行时错误来进行修改。

func postMessage(message: String, withName name: String) {
    if name != nil && message != nil {
        var postString: NSMutableString = NSMutableString.stringWithString(kPostURL)
        postString.appendString("?\(kName)=\(name)")
        postString.appendString("&\(kMessage)=\(message)")
        postString.setString(postString.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding))
        var request: NSMutableURLRequest = NSMutableURLRequest(uRL: NSURL.URLWithString(postString))
        request.setHTTPMethod("POST")
        postConnection = NSURLConnection(request: request, delegate: self, startImmediately: true)
    }
}

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