如何比较此2D字符数组和1D字符数组？
array1[0][0] = 'a',
array1[0][4] = null,
array1[1][1] = null
array1[2][0] = 'b'
array1[3][5] = null
and so on
array2[0] = 'a'
array2[1] = 'b'
array2[2] = 'a'
只需运行一个嵌套循环并检查每次即可。
char[] array2 = new char[3];
array2[0] = 'a';
array2[1] = 'b';
array2[2] = 'a';
char[][] array1 = new char[6][6];
array1[0][0] = 'a';
array1[0][4] = 'q';
array1[1][1] = 'r';
array1[2][0] = 'b';
array1[3][5] = 's';
for (int i = 0; i < array2.length; ++i) {
char ch = array2[i];
for (int j = 0; j < array1.length; ++j) {
for (int k = 0; k < array1[j].length; ++k) {
if (ch == array1[j][k])
System.out.println("array2[" + i + "] matches with array1[" + j + "][" + k + "] with char being " + ch);
}
}
}
Output :
array2[0] matches with array1[0][0] with char being a
array2[1] matches with array1[2][0] with char being b
array2[2] matches with array1[0][0] with char being a
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