我有一个控制器动作,如下所示:
public ActionResult Content(string slug)
{
var content = contentRepository.GetBySlug(slug);
return View(content);
}
我希望将此类网址发送给我的操作:
这是我的RegisterRoutes方法:
public static void RegisterRoutes(RouteCollection routes)
{
routes.IgnoreRoute("{resource}.axd/{*pathInfo}");
routes.MapRoute(
name: "Default",
url: "{controller}/{action}/{id}",
defaults: new { controller = "Page", action = "Index", id = UrlParameter.Optional }
);
routes.MapRoute(
name: "GetContent",
url: "{slug}",
defaults: new { controller = "Page", action = "Content", slug = "" }
);
}
但这不起作用,我在做什么错?
谢谢,
1将slug路由置于默认路由之上,如果不设置,则从不执行slug路由
2 slug不能为空,如果为空,则URL为http:// localhost /,它必须为默认路由
routes.MapRoute(
name: "slug",
url: "{slug}",
defaults: new { controller = "Home", action = "show" },
constraints: new{ slug=".+"});
routes.MapRoute(
name: "Default",
url: "{controller}/{action}/{id}",
defaults: new { controller = "Home", action = "Index", id = UrlParameter.Optional });
而且我认为不要选择“ Content”作为动作名称,因为在基类中有一个Content Method
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