因此,我尝试使用会返回JSON响应的League of Legends API。我没有使用像Jakcson或GSON这样的花哨的lib,
{"type":"champion","version":"5.11.1","data":{"Thresh":{"id":412,"key":"Thresh","name":"Thresh","title":"the Chain Warden"},"Aatrox":{"id":266,"key":"Aatrox","name":"Aatrox","title":"the Darkin Blade"},"Tryndamere":{"id":23,"key":"Tryndamere","name":"Tryndamere","title":"the Barbarian King"},"Gragas":{"id":79,"key":"Gragas","name":"Gragas","title":"the Rabble Rouser"}}}
但是,当我尝试访问数据对象中的对象时,必须在代码中明确列出密钥名称。
而且键名实际上是动态的,因此不切实际。
有什么方法可以在不显式调用键名称的情况下获取数据对象中的所有对象?
这是我的Java客户端代码
public String callApi(String API_URL) throws IOException {
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
OkHttpClient client = new OkHttpClient();
Request request = new Request.Builder()
.url(API_URL)
.build();
Response response = client.newCall(request).execute();
return response.body().string();
}
public void buttonClick(View view) throws IOException, JSONException {
String API_URL = "https://global.api.pvp.net/api/lol/static-data/tr/v1.2/champion?locale=en_US&api_key=my_key_here";
String champions_json = callApi(API_URL);
Log.i("summoner",champions_json);
JSONObject json= new JSONObject(champions_json);
JSONObject data = json.getJSONObject("data");
Log.i("summoner", String.valueOf(data));
List<String> champions = new ArrayList<String>();
champions.add("Garen");
champions.add("Aatrox");
champions.add("Thresh");
for (String champion : champions) {
JSONObject object = new JSONObject(String.valueOf(data));
String name = object.getString(champion);
Log.i("summoner",name);
}
}
使用获取JSON对象的密钥keys()
,然后对其进行迭代。
Iterator<String> keys = json.keys();
while (keys.hasNext())
{
// Get the key
String key = keys.next();
// Get the value
JSONObject value = json.getJSONObject(key);
// Do something...
}
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我来说两句