我有一个过滤表的表单,并且我希望表单条目构建一个sqlalchemy语句。
因为我有“无过滤器”选项,所以我不能仅将表单字段放入过滤器(“此处的表单字段”)。但是必须有比进行像这样的每个排列更好的方法
AT= list(set([h.assigned for h in models.Request.query.all()]))
AT.append('No Filter')
form.assigned.choices=zip(AT,AT)
requestlist= models.Request.query.all()
if form.validate_on_submit():
if form.status.data=='No Filter' and form.assigned.data=='No Filter' and form.requestor.data=='No Filter':
requestlist= models.Request.query.all()
elif form.status.data != 'No Filter' and form.assigned.data=='No Filter' and form.requestor.data=='No Filter':
requestlist = db.session.query(models.Request).filter(models.Request.status.like(form.status.data)).all()
elif form.status.data == 'No Filter' and form.assigned.data!='No Filter' and form.requestor.data=='No Filter':
requestlist = db.session.query(models.Request).filter(models.Request.assigned.like(form.assigned.data)).all()
elif form.status.data == 'No Filter' and form.assigned.data=='No Filter' and form.requestor.data!='No Filter':
requestlist = db.session.query(models.Request).filter(models.Request.requestedBy.like(form.requestor.data)).all()
elif form.status.data != 'No Filter' and form.assigned.data=='No Filter' and form.requestor.data!='No Filter':
requestlist = db.session.query(models.Request).filter(models.Request.requestedBy.like(form.requestor.data))\
.filter(models.Request.status.like(form.status.data)).all()
elif form.status.data == 'No Filter' and form.assigned.data !='No Filter' and form.requestor.data!='No Filter':
requestlist = db.session.query(models.Request).filter(models.Request.requestedBy.like(form.requestor.data))\
.filter(models.Request.assigned.like(form.assigned.data)).all()
elif form.status.data != 'No Filter' and form.assigned.data !='No Filter' and form.requestor.data =='No Filter':
requestlist = db.session.query(models.Request).filter(models.Request.status.like(form.status.data))\
.filter(models.Request.assigned.like(form.assigned.data)).all()
elif form.status.data != 'No Filter' and form.assigned.data !='No Filter' and form.requestor.data !='No Filter':
requestlist = db.session.query(models.Request).filter(models.Request.status.like(form.status.data))\
.filter(models.Request.requestedBy.like(form.requestor.data))\
.filter(models.Request.assigned.like(form.assigned.data)).all()
您可以filter(...)
一个接一个地添加多个子句:
if form.validate_on_submit():
requestlist = models.Request.query
if form.status.data != 'No Filter':
requestlist = requestlist.filter(models.Request.status.like(form.status.data))
if form.assigned.data != 'No Filter':
requestlist = requestlist.filter(models.Request.assigned.like(form.assigned.data))
if form.requestor.data != 'No Filter':
requestlist = requestlist.filter(models.Request.requestedBy.like(form.requestor.data))
return requestlist.all()
或更笼统地说,您可以执行以下操作:
field_names = ['status', 'assigned', 'requestor']
if form.validate_on_submit():
requestlist = models.Request.query
for field in field_names:
f_value = getattr(form, field).data
if f_value != 'No Filter':
requestlist = requestlist.filter(getattr(models.Request, field).like(f_value))
return requestlist.all()
我看到的唯一问题是,有时表单和模型上的名称不匹配。一个示例是requestedBy
和requestor
。在这种情况下,您可以定义字典而不是中的列表field_names
。
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我来说两句