从数组中选择最小数量并删除其余的JavaScript

debugcn 发表于 Dev

用户名

我有一个非常复杂的数组，需要转换为特定格式。该数组如下所示：

arr = [["name1",51,1,"code1",3],["name2",52,0,"code2",4,"code3",6],["name3",51,2,"code4",3,"code5",6,"code6",1],["name4",55,5,"code7",7,"code8",1],["name5",54,2,"code9",5,"code10",8]];

我的输出需要中的每个数组仅包含5个值-3个第一个值始终与输入中的相同。接下来的2个值应包含代码和数组其余部分中的最小值。因此，这种情况下的输出将如下所示：

output = [["name1",51,1,"code1",3],["name2",52,0,"code2",4],["name3",51,2,"code6",1],["name4",55,5,"code8",1],["name5",54,2,"code9",5]];

首先，我认为最好是使用for和if指令的循环，但是我不知道以后如何处理。

for (i=0; i<arr.length; i++) {
    if (arr[i]>5) {
     //dont know what to put here   
    }
}

贝菲兹

我的解决方案：

arr = [
    ["name1",51,1,"code1",3],
    ["name2",52,0,"code2",4,"code3",6],
    ["name3",51,2,"code4",3,"code5",6,"code6",1],
    ["name4",55,5,"code7",7,"code8",1],
    ["name5",54,2,"code9",5,"code10",8]
];

function process_array(in_array) {
    
  var output = [];
  
  /* check each element in array */
  in_array.forEach(function(sub_array){
      
      /* store new sub array here*/
      var last_sub_out = [];
      
      var code;
      var lowest_num = Number.MAX_VALUE;
      
      /*  check sub array
          @value is value of sub_array
          @index is index of that value. 
      */
      sub_array.forEach(function(value, index){
          
          /* add first 3 values */
          if(index < 3) {
              last_sub_out.push( value );
              return;
          }
          
          /* checking only numbers(even index: 4,6,8, ...) */
          if(index % 2 == 0) {
              if(value < lowest_num) {
                  code = sub_array[index - 1];
                  lowest_num = value;
              }
          }
      });
      
      /* add found code with lowest number */
      last_sub_out.push(code, lowest_num);
      
      output.push( last_sub_out );
      
      /* LOG */
      document.write(last_sub_out.join(', ') + "</br>");
  });
  return output;
}

var out = process_array(arr);