排序似乎不起作用

这段代码是用编写的C++。我有以下结构：

#include <vector>
#include <algorithm>
#include <iostream>
using namespace std;

struct Data
{
    int h, b, w;

    Data(int _h, int _b, int _w) : h(_h), b(_b), w(_w)
    {}

    bool operator<(const Data& other) const
    {
        bool overlap = (other.b >= b && other.b <= w) ||
            (other.w >= b && other.w <= w) ||
            (other.b < b && other.w > w);
        if (overlap)
        {
            return h < other.h;
        }

        return h > other.h;
    }
};

在operator<将用于排序。想法是从最高-h到最低-h进行排序，除非两个变量之间b或w比较变量之间没有任何重叠。剩余代码：

vector <int> getOrdering(vector <int> height, vector <int> bloom, vector <int> wilt)
{
    vector<Data> vdata;

    for (int i = 0; i < height.size(); i++)
    {
        vdata.push_back(Data(height[i], bloom[i], wilt[i]));
    }

    sort(vdata.begin(), vdata.end());
    vector<int> ans;
    for (Data data : vdata)
    {
        ans.push_back(data.h);
    }

    return ans;
}

int main()
{
    vector <int> p0 = { 1, 2, 3, 4, 5, 6 };
    vector <int> p1 = { 1, 3, 1, 3, 1, 3 };
    vector <int> p2 = { 2, 4, 2, 4, 2, 4 };

    vector<int> ans = getOrdering(p0, p1, p2);

    for (int a : ans)
    {
        cout << a << ' ';
    }
    cout << endl;

    return 0;
}

我编写operator<函数的方式，代码应该输出2 4 6 1 3 5。但是输出是6 5 4 3 2 1。我正在使用Visual Studio 2013 Ultimate。

调试完该operator<函数后，我发现它正被Data对象调用，如下所示：

1st call: this->h = 2, other.h = 1
2nd call: this->h = 1, other.h = 2
3rd call: this->h = 3, other.h = 2
4th call: this->h = 2, other.h = 3
5th call: this->h = 4, other.h = 3
6th call: this->h = 3, other.h = 4
7th call: this->h = 5, other.h = 4
8th call: this->h = 4, other.h = 5
9th call: this->h = 6, other.h = 5
10th call: this->h = 5, other.h = 6

请注意，当Data对象的h值为1、3或5时，它们的b和w值相同。它们将按h的升序排序。同去真正的Data对象其H值是2,4和6，但在operator<()没有两个Data对象都比较过其H值是一样的！1比2，2比3，3比4，依此类推。因此，overlap变量始终为false。sort()如果Data比较h值相同的对象，结果将是不同的-但这从未发生！

关于编译器这种行为的任何解释吗？