所有这些都是为了防万一:
情况1:
echo "${name}:${identity}:${hp}:$now:"0"" >> info.txt # write to info.txt
所以我会有这样的事情: Tom:8:987654:commission:0 # i assign it to 0 first
情况2:
echo -n "Enter employee's name:"
read name
S=`grep $name info.txt`;
if test -z $S
then
echo "No details with employee name $name"
else
echo "$S" | cut -d: -f4 // display 4th column.
echo
echo -n "Enter hourly wage: "; read wage;
echo -n "Enter hours worked this week: "; read hours;
pay=$hours-40*$wage;
echo -n "To update next payroll : press Y else N to go main menu: "
read option
case "$option" in
[Yy]*) echo "Payroll have been updated."
echo grep $name | sed -i s/\:*$/$pay/n info.txt //error
;;
[Nn]*)
echo "Press Enter to view the Main"
esac
fi
我的文本文件如下所示:
Tom:8:987654:commission:0
Tommy:7:12379813:hourly:0
Fan:5:2132131:salaried:0
我试图将最后一列的值替换为$ pay(并非所有列仅由用户指定名称)假设$ pay是10,$ name是Tommy
这是预期的文本文件:
Tom:8:987654:commission:0
Tommy:7:12379813:hourly:10
Fan:5:2132131:salaried:0
但是我得到了这个错误:sed: -e expression #1, char 15: unknown option to
s'`
我正在在Ubuntu终端上进行操作。
替换整行:
sed -e "/$name/s/[0-9]*$/$pay/" -i info.txt
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我来说两句