将代码从JavaScript转换为PHP

debugcn 发表于 Dev

标记

我的代码中存在诸如“ <i585>”之类的东西。我想从“ i”到“>”获取字符串。并替换为“ 585”而不是“ <i585>”。我用JavaScript编写了一些代码。

<script type="text/javascript">
var foo ="M <i585> <i646>";

while (foo.indexOf("<i") != -1) {

    var indexBaş = foo.indexOf("<i");

    var indexSon = foo.indexOf(">", indexBaş);

    var id = foo.substring(indexBaş + 2, indexSon);

    foo = foo.substring(0 , indexBaş) + id + foo.substring(indexSon + 1 , foo.lenght);

}
document.write(foo);
</script>

但是我必须将此代码转换为php。所以我写这段代码

$foo ="M <i585> <i646>";

$start = 0;
$kacTane= 0;

for($i = 0 ; $i < strlen($foo) ; $i++ ) {
    if($foo[$i] == "<") {
        if(($foo + 1 )< strlen($foo)) {
            if($foo[$i+1] == "i") {
                $kacTane++;
            }
        }

    }
}

for($i = 0; $i < $kacTane; $i++) {
    $ilkIndex = strpos($foo , "<" , $start);

    $sonindex = strpos($foo , ">" , $ilkIndex);

    $id = substr($foo , $ilkIndex + 2 ,( $sonIndex -3) - $ilkIndex  );

    $first = substr($foo , 0 , $ilkIndex +2);
    $second = substr($foo , $sonIndex + 1 , strlen($foo) - $sonIndex - 1 );

    $foo = "$first$id$second";
    $start = ($sonindex + 1);

}
echo $foo;

但这是行不通的。

对不起，英语不好。

沃尔沃

也许一些预赛？

$foo ="M <i585> <i646>";
preg_match_all('/<i(.*?)>/',$foo, $results); //search for all numbers

$patterns = array();
$replace = array();
foreach ($results[1] as $result){
  $patterns[] = '/<i'.$result.'>/';
  switch ($result) {
    case '585':
      $result = '333';
      break;
    case '646':
      $result = '444';
      break;
  }
  $replace[] = '<i'.$result.'>';
}

$replace = preg_replace($patterns, $replace, $foo); //if you just want to repleace then this single line (+ arrays) are all you need.
echo '<br>'.$replace;