我想从字符串中删除静态文本-iOS

debugcn 发表于 Dev

阿杰·文卡特（Ajay Venkat）

嗨，我有一个新闻阅读器，但我不断收到这样的字符串-

two New York police officers shot dead in 'ambush'

I want the string two New York police officers shot dead in ambush

我如何从＆扫描到; 然后删除发生的扫描。

我创建了这样的扫描仪-

NSString *webString222222 = filteredTitle2;
        NSScanner *stringScanner222222 = [NSScanner scannerWithString:webString222222];
        NSString *content222222 = [[NSString alloc] init];
        [stringScanner222222 scanUpToString:@"&" intoString:Nil];
        [stringScanner222222 scanUpToString:@";" intoString:&content222222];
        NSString *filteredTitle222 = [content222222 stringByReplacingOccurrencesOfString:content222222 withString:@""];
        NSString *filteredTitle22 = [filteredTitle222 stringByReplacingOccurrencesOfString:@"&" withString:@""];

但是，当我执行此代码时，整个文本消失了！每个字。当我在NSLog中检查标题时，这是唯一的＆登录，也是唯一的; 登录那里！我不确定我在哪里错了。

sha

您可以NSRegularExpression用来构建适当的匹配模式：

NSString *pattern = @"\\&#[0-9]+;";
NSString *str = @"two New York police officers shot dead in &#039;ambush&#039;";

NSLog(@"Original test: %@",str);
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression
                              regularExpressionWithPattern:pattern
                              options:NSRegularExpressionCaseInsensitive error:&error];
if (error != nil)
{
    NSLog(@"ERror: %@",error);
} 
else 
{
    NSString *replaced = [regex stringByReplacingMatchesInString:str
                                                         options:0
                                                           range:NSMakeRange(0, [str length])
                                                    withTemplate:@""];

    NSLog(@"Replaced test: %@",replaced);
}

参见https://developer.apple.com/library/ios/documentation/Foundation/Reference/NSRegularExpression_Class/index.html

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