将图像存储在C＃Window Form App的同一文件夹中

debugcn 发表于 Dev

奥拜杜拉·拉菲克（Obaidullah Rafiq）

我是C＃的新手。我想从任何地方获取图像，在图片框中显示它，然后将其保存在同一文件夹（项目文件夹）中。但是它给出了错误。即“通用错误发生在GDI +中”。我已经看了很多帖子。但是我无法解决这个问题。我的代码如下。

 private void btnImage_Click(object sender, EventArgs e)
    {
        try
        {
            OpenFileDialog open = new OpenFileDialog();
            open.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp";
            if (open.ShowDialog() == DialogResult.OK)
            {
                Bitmap bit = new Bitmap(open.FileName);
                pictureBox1.Image = bit;
                var imagestudent = pictureBox1.Image;
                string extension = Path.GetFileNameWithoutExtension(open.FileName);
                extension += DateTime.Now.ToString("yyyy-MM-dd_HH_mm_ss") + Path.GetExtension(open.FileName);

                imagestudent.Save(@"PicturesofStudent\" + extension);
            }

        }
        catch (Exception ex)
        {
            MessageBox.Show(ex.Message);
        }
    }

我该怎么办？

阿德南·乌默（Adnan umer）

发生这种情况是因为您忘记了放在.文件扩展名之前。试试这个

string extension = Path.GetFileNameWithoutExtension(open.FileName);
extension += DateTime.Now.ToString("yyyy-MM-dd_HH_mm_ss") + "." + Path.GetExtension(open.FileName);

编辑

您也可以尝试File.Copy而不是调用PictuteBox.Save方法。：

OpenFileDialog open = new OpenFileDialog();
open.Filter = "Image Files(*.jpg; *.jpeg; *.gif; *.bmp)|*.jpg; *.jpeg; *.gif; *.bmp";
if (open.ShowDialog() == DialogResult.OK)
{
    Bitmap bit = new Bitmap(open.FileName);
    pictureBox1.Image = bit;
    var imagestudent = pictureBox1.Image;
    string fileName = Path.GetFileNameWithoutExtension(open.FileName) + 
                        DateTime.Now.ToString("yyyy-MM-dd_HH_mm_ss") +
                        Path.GetExtension(open.FileName);

    string directory = "PicturesofStudent";
    if (!Directory.Exists(directory))
        Directory.CreateDirectory(directory);

    File.Copy(open.FileName, Path.Combine(directory, fileName));
}