我是Json的新手,并试图了解如何使用Json.Net对其进行解析。我尝试为json输入创建对象,但被卡住了。我不太确定如何解析输入内容,因此可以对其进行迭代并输出季节编号和剧集名称。
谁能指出我正确的方向?
杰森:
{
"data":{
"1921":{
"1":{
"airdate":"1921-03-20",
"name":"Cleaning Up!!?",
"quality":"N/A",
"status":"Wanted"
},
"2":{
"airdate":"1921-03-20",
"name":"Kansas City Girls Are Rolling Their Own Now",
"quality":"N/A",
"status":"Wanted"
},
"3":{
"airdate":"1921-03-20",
"name":"Did You Ever Take a Ride Over Kansas City Street 'in a Fliver'",
"quality":"N/A",
"status":"Wanted"
},
"4":{
"airdate":"1921-03-20",
"name":"Kansas City's Spring Clean-Up",
"quality":"N/A",
"status":"Wanted"
}
},
"1923":{
"1":{
"airdate":"2013-05-16",
"name":"Alice's Wonderland - aka - Alice in Slumberland",
"quality":"Unknown",
"status":"Downloaded"
}
}
},
"message":"",
"result":"success"
}
代码:
static void Main(string[] args)
{
RootObject data = JsonConvert.DeserializeObject<RootObject>(System.IO.File.ReadAllText(@"C:\Users\Benjamin\Desktop\json\input.txt"));
foreach (var e in data)
{
// Being able to output Season and Episode name like:
// 1921 - Cleaning Up!!?
}
}
public class RootObject
{
public Dictionary<int, Season> data { get; set; }
public string message { get; set; }
public string result { get; set; }
}
public class Season
{
public Dictionary<string, Episode> number { get; set; }
}
public class Episode
{
public string airdate { get; set; }
public string name { get; set; }
public string quality { get; set; }
public string status { get; set; }
}
更改您的RootObject
:
public class RootObject
{
public Dictionary<int, Dictionary<string, Episode>> data { get; set; }
public string message { get; set; }
public string result { get; set; }
}
然后,您可以执行以下操作:
RootObject root = JsonConvert.DeserializeObject<RootObject>(data);
foreach (var s in root.data)
{
foreach (var e in s.Value)
{
Console.WriteLine(string.Format("{0} - {1}", s.Key, e.Value.name));
// access whatever properties you want here...
}
}
请注意,我们已删除了该Season
对象,因为JSON.net无法映射到该属性,number
因为它不是原始JSON中的属性(您可以使其工作,但是需要自定义序列化一些摆弄)。
如果您真的想要LINQ解决方案,则类似于:
root.data.ToList().ForEach(s =>
{
s.Value.ToList().ForEach(e =>
{
Console.WriteLine(string.Format("{0} - {1}", s.Key, e.Value.name));
});
});
实现相同的目的,但是需要将字典复制到列表中,如果字典很大,则可能会出现问题。
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