如何调用JSON Web服务？

debugcn 发表于 Dev

拉胡尔·马特（Rahul Matte）

我正在尝试调用此Web服务，但其响应为null

<script type="text/javascript">
    jQuery(document).ready(function(){
        var user = {nick :"rajesh", password:"123456", device_id:"123456677"};
        jQuery.ajax({
            type: "post",
            data :JSON.stringify(user),
            url: "http://localhost:81/sazpin/user/users/index.json",
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            success: function(data) {
                console.log(data);
            }
        });
    });
</script>

我的httppost客户端是

HttpClient httpClient = new DefaultHttpClient();

// post header
HttpPost httpPost = new HttpPost(url);                  
httpPost.setEntity(se);        
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");

请有人帮助我。如何调用此Web服务并获得响应？

履带式

试试这个代码。首先创建您的AsyncTask。

public class ResquestJSON extends AsyncTask<String, Void, String>{
JSONObject jsonObject = new JSONObject();
String response;

protected String doInBackground(String... params){
    HttpPost httpPost = new HttpPost("http://192.168.10.101:8090/download");//your webservice url here
    HttpClient httpClient = new DefaultHttpClient();
    HttpContext httpContext = new BasicHttpContext();
    try {
        jsonObject.put("firstParam", params[0]);
        jsonObject.put("secondParam", params[1]);

        StringEntity se = new StringEntity(jsonObject.toString());
        httpPost.addHeader("Content_Type", "application/json");
        httpPost.setEntity(se);
        HttpResponse httpResponse = httpClient.execute(httpPost, httpContext);

        HttpEntity entity = httpResponse.getEntity();

        if (entity!=null){
            response = EntityUtils.toString(entity);
            entity.consumeContent();
            httpClient.getConnectionManager().shutdown();
        }
    } catch (JSONException|IOException|IllegalArgumentException e) {
        return UtilityConstants.ERROR;
    }
    return response;
}

现在从这样的活动中调用此AsyncTask方法。

String response = new ResquestJSON().execute(firstParam, secondParam).get();
JSONObject obj = new JSONObject(response);
String nick = obj.getString("nick");
String password = obj.getString("password");
String deviceId = obj.getString("deviceId");

希望对您有所帮助。

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