将html页中的\ n替换为python LXML中的空格

debugcn 发表于 Dev

2 8

我有一个不清楚的xml，并使用python lxml模块对其进行处理。我想在进行任何处理之前将所有\n内容替换为space，该如何处理所有元素的文本。

编辑我的xml示例：

<root>
    <a> dsdfs\n dsf\n sdf\n</a>
    <bds> 
        <d>sdf\n\n\n\n\n\n</d>
        <d>sdf\n\n\nsdf\nsdf\n\n</d>
    </bds>
    ....
    ....
    ....
    ....
</root>

当我打印ittertext时，我不会在输出中得到这个：

root = #get root element
for i in root.ittertext():
   print i

dsdfs  dsf  sdf
dsdfs  dsf  sdf
sdf  nsdf sdf

sk11

下面的代码将xml解析为字符串，然后替换\n为space，然后写入新的xml文件。您可以在这之间进行其他处理，具体取决于您要执行的操作。

from lxml import etree 
tree = etree.parse('some.xml') 
root = tree.getroot()
# Get the whole XML content as  string
xml_in_str = etree.tostring(root)

# Replace all \n with space
new_xml_data = xml_in_str.replace(r'\n', ' ')

# Do the processing with the new_xml_data string which is formatted

# Maybe also write to a new XML file, without the \n
with open('newxml.xml', 'w') as f:
    f.write(new_xml_data)

some.xml 看起来像：

<root>
    <a> dsdfs\n dsf\n sdf\n</a>
    <bds> 
        <d>sdf\n\n\n\n\n\n</d>
        <d>sdf\n\n\nsdf\nsdf\n\n</d>
    </bds>
    <bds> 
        <d>sdf\n\n\n\n\n\n</d>
        <d>sdf\n\n\nsdf\nsdf\n\n</d>
    </bds>
    <bds> 
        <d>sdf\n\n\n\n\n\n</d>
        <d>sdf\n\n\nsdf\nsdf\n\n</d>
    </bds>
</root>

newxml.xml 看起来像：

<root>
    <a> dsdfs  dsf  sdf </a>
    <bds> 
        <d>sdf      </d>
        <d>sdf   sdf sdf  </d>
    </bds>
    <bds> 
        <d>sdf      </d>
        <d>sdf   sdf sdf  </d>
    </bds>
    <bds> 
        <d>sdf      </d>
        <d>sdf   sdf sdf  </d>
    </bds>
</root>