AngularJS根据所选项目动态填充json中的详细信息

我正在尝试创建一个页面，在该页面中，列表组中的项目很少，选择后应显示更多详细信息。

请在此处查看示例http://plnkr.co/edit/Oava3pA9OTsm80K58GdT?p=preview

如何根据列表组中选择的项目填充json文件中的详细信息？

到目前为止，这就是我所拥有的。

的HTML：

<div ng-controller=ItemsController>
    <h3>Test</h3>
    <div class="row">
      <div class="col-md-4">
        <div class="panel panel-default">
          <ul class="list-group">
            <a class="list-group-item" ng-repeat="item in itemDetails">{{item.name}}</a>
          </ul>
        </div>
      </div>

      <div class="col-md-8">
        <div class="panel panel-default">
          <h2>Name: </h2>
          <br />Address Line 1:
          <br />Address Line 2:
          <br />Suburb:
          <br />Phone:
          <br />Email:
        </div>
      </div>
    </div>
  </div>

脚本：

var myItemsApp = angular.module('myItemsApp', []);

myItemsApp.factory('itemsFactory', ['$http', function($http){
  var itemsFactory ={
    itemDetails: function() {
      return $http(
      {
        url: "mockItems.json",
        method: "GET",
      })
      .then(function (response) {
        return response.data;
        });
      }
    };
    return itemsFactory;

}]);


myItemsApp.controller('ItemsController', ['$scope', 'itemsFactory', function($scope, itemsFactory){
  var promise = itemsFactory.itemDetails();

    promise.then(function (data) {
        $scope.itemDetails = data;
        console.log(data);
    });
}]);

json：

[
   {
      "$id":"1",
      "name":"Test itemName 1",
      "themeName":"ASD",
      "addressLine1":"18 Banksia Street",
      "addressLine2":null,
      "suburb":"Heidelberg",
      "state":"VIC",
      "postalCode":"3084",
      "contactPhone":"+61 3 123456",
      "emailAddress":"[email protected]"
   },
   {
      "$id":"2",
      "name":"Test itemName 2",
      "themeName":"WER",
      "addressLine1":"11 Riverview Place",
      "addressLine2":"Metroplex on Gateway",
      "suburb":"Murarrie",
      "state":"QLD",
      "postalCode":"4172",
      "contactPhone":"1300 73123456",
      "emailAddress":"[email protected]"
   },
   {
      "$id":"3",
      "name":"Test itemName 3",
      "themeName":"ERT",
      "addressLine1":"60 Waterloo Road",
      "addressLine2":null,
      "suburb":"North Ryde",
      "state":"NSW",
      "postalCode":"2113",
      "contactPhone":"123456",
      "emailAddress":"[email protected]"
   }
]

任何帮助将不胜感激。

我对编程非常陌生。如果我做错了，也请随意选择实现此目的的其他方法。