我收到以下错误：
FieldError at /blog/1/first-post/
Cannot resolve keyword u'slug' into field. Choices are: article, date, id, likes
Request Method: GET
Request URL: http://127.0.0.1:8000/blog/1/first-post/
Django Version: 1.6.2
Exception Type: FieldError
Exception Value:
Cannot resolve keyword u'slug' into field. Choices are: article, date, id, likes
我的模特：
class Article(models.Model):
title = models.CharField(max_length=20)
body = models.TextField()
image = models.ImageField(upload_to="/", blank=True, null=True)
slug = models.SlugField()
def save(self, *args, **kwargs):
if not self.id:
self.slug = slugify(self.title)
super(Article, self).save(*args, **kwargs)
def get_absolute_url(self):
return reverse('article_detail', kwargs={'slug':self.slug, 'id':self.id})
def __unicode__(self):
return self.title
class Detail(models.Model):
article = models.ForeignKey(Article)
date = models.DateField()
likes = models.IntegerField()
def __unicode__(self):
return "%s %s" % (self.article.title, self.likes)
def get_absolute_url(self):
return reverse('detail_article', kwargs={'id':self.id})
看法：
class ArticleDetail(DetailView):
model = Detail
template_name = "article_detail.html"
context_object_name = "details"
def get_queryset(self):
print self.kwargs['slug']
a = Article.objects.get(slug=self.kwargs['slug'])
# print Details.object.get()
# print Detail.objects.filter(article__slug=self.kwargs['slug']) fails with same error
return Detail.objects.filter(article=a)
urls.py（位于博客应用程序内部）：
urlpatterns = patterns('',
url(r'all$', ArticleList.as_view(), name='blog_all'),
url(r'^(?P<id>\d+)/(?P<slug>[-\w\d]+)/$', ArticleDetail.as_view(), name='article_detail'),
url(r'^detail/?(P<id?\d+)/$', DetailArticle.as_view(), name='detail_article'),
url(r'^create$', ArticleCreateView.as_view(), name='blog_create'),
)
基本上，an的detailViewarticle instance将显示与detail具有外键关系的模型的内容article model。article实例的详细信息视图显示该实例不是传统的方式。
模板在这里：
{% extends "base.html" %}
{% block content %}
{% for detail in details %}
<p>{{ detail.article.title }}</p>
<p>{{ detail.date }}</p>
<p>{{ detail.likes }}</p>
{% endfor %}
{% endblock %}
解决方案：您需要将url中的slug参数重命名为其他名称，或者在您的视图中将slug_url_kwarg设置为其他一些值-而不是'slug'
说明：当您添加到url时，django会尝试通过slug获取对象，并且您的模型Detail没有任何slug字段。
链接到Django代码：https : //github.com/django/django/blob/master/django/views/generic/detail.py#L33
更新
在SingleObjectMixin中：
slug = self.kwargs.get(self.slug_url_kwarg, None)
...
elif slug is not None:
slug_field = self.get_slug_field()
queryset = queryset.filter(**{slug_field: slug})
所以django从您的网址中获取子弹，尝试从Detail模型中获取子弹字段，但失败
您的视图需要重写slug_url_kwarg属性：
class ArticleDetail(DetailView):
model = Detail
template_name = "article_detail.html"
context_object_name = "details"
slug_url_kwarg = "not_slug" # this attribute
def get_queryset(self):
print self.kwargs['slug']
a = Article.objects.get(slug=self.kwargs['slug'])
# print Details.object.get()
# print Detail.objects.filter(article__slug=self.kwargs['slug']) fails with same error
return Detail.objects.filter(article=a)
但我认为更好的方法是更改URL中的属性：
url(r'^(?P<id>\d+)/(?P<article_slug>[-\w\d]+)/$', ArticleDetail.as_view(), name='article_detail'),
并从视图kwargs获取article_slug
本文收集自互联网，转载请注明来源。
如有侵权，请联系[email protected] 删除。
我来说两句