我正在尝试通过他们的PHP SDK在Amazon S3上上传图片。所以我做了一个小脚本。但是,我的脚本不起作用,我的异常也没有向我发送任何错误消息。
我是AWS的新手,感谢您的帮助。
这是代码:
Config.php
<?php
return array(
'includes' => array('_aws'),
'services' => array(
'default_settings' => array(
'params' => array(
'key' => 'PUBLICKEY',
'secret' => 'PRIVATEKEY',
'region' => 'eu-west-1'
)
)
)
);
?>
Index.php
<?php
//Installing AWS SDK via phar
require 'aws.phar';
use Aws\S3\S3Client;
use Aws\S3\Exception\S3Exception;
$bucket = 'infact';
$keyname = 'myImage';
// $filepath should be absolute path to a file on disk
$filepath = 'image.jpg';
// Instantiate the client.
$s3 = S3Client::factory('config.php');
// Upload a file.
try {
$result = $s3->putObject(array(
'Bucket' => $bucket,
'Key' => $keyname,
'SourceFile' => $filePath,
'ContentType' => 'text/plain',
'ACL' => 'public-read',
'StorageClass' => 'REDUCED_REDUNDANCY'
));
// Print the URL to the object.
echo $result['ObjectURL'] . "\n";
} catch (S3Exception $e) {
echo $e->getMessage() . "\n";
}
?>
编辑:我现在正在使用此代码,但仍无法正常工作。我什至没有错误或异常消息。
<?php
require 'aws.phar';
use Aws\S3\S3Client;
use Aws\S3\Exception\S3Exception;
$bucket = 'infactr';
$keyname = 'sample';
// $filepath should be absolute path to a file on disk
$filepath = 'image.jpg';
// Instantiate the client.
$s3 = S3Client::factory(array(
'key' => 'key',
'secret' => 'privatekey',
'region' => 'eu-west-1'
));
try {
// Upload data.
$result = $s3->putObject(array(
'Bucket' => $bucket,
'Key' => $keyname,
'SourceFile' => $filePath,
'ACL' => 'public-read',
'ContentType' => 'image/jpeg'
));
// Print the URL to the object.
echo $result['ObjectURL'] . "\n";
} catch (S3Exception $e) {
echo $e->getMessage() . "\n";
}
?>
尝试这样的事情(来自AWS docs):
<?php
require 'aws.phar';
use Aws\S3\S3Client;
use Aws\S3\Exception\S3Exception;
$bucket = '<your bucket name>';
$keyname = 'sample';
// $filepath should be absolute path to a file on disk
$filepath = '/path/to/image.jpg';
// Instantiate the client.
$s3 = S3Client::factory(array(
'key' => 'your AWS access key',
'secret' => 'your AWS secret access key'
));
try {
// Upload data.
$result = $s3->putObject(array(
'Bucket' => $bucket,
'Key' => $keyname,
'SourceFile' => $filepath,
'ACL' => 'public-read'
));
// Print the URL to the object.
echo $result['ObjectURL'] . "\n";
} catch (S3Exception $e) {
echo $e->getMessage() . "\n";
}
?>
只要您拥有正确的凭据,它对我来说就很好。请记住,密钥名称是S3中文件的名称,因此,如果要使密钥具有与文件相同的名称,则必须执行以下操作:$keyname = 'image.jpg';
。另外,jpg通常不是plain/text
文件类型,您可以忽略该Content-type
字段,也可以只指定以下内容:image/jpeg
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我来说两句