我有一个音频文件,正在将其转换为字节数组,但是您无法确定该字节值何时真正在歌曲中播放。因此,我尝试将其扩展到歌曲的整个长度。
因此,在播放歌曲时,它会输出字节值。这怎么可能?
到目前为止,这是我的代码:
public class Main {
private static final String FILENAME = "assets/pf.wav";
private static double[] endResult = null;
public static void convert() throws IOException{
ByteArrayOutputStream out = new ByteArrayOutputStream();
BufferedInputStream in = new BufferedInputStream(new FileInputStream(FILENAME));
int read;
byte[] buff = new byte[1024];
while ((read = in.read(buff)) > 0)
{
out.write(buff, 0, read);
}
out.flush();
byte[] audioBytes = out.toByteArray();
endResult = calculateFFT(audioBytes);
}
public static double[] calculateFFT(byte[] signal)
{
final int mNumberOfFFTPoints =1024;
double mMaxFFTSample;
double temp;
Complex[] y;
Complex[] complexSignal = new Complex[mNumberOfFFTPoints];
double[] absSignal = new double[mNumberOfFFTPoints/2];
for(int i = 0; i < mNumberOfFFTPoints; i++){
temp = (double)((signal[2*i] & 0xFF) | (signal[2*i+1] << 8)) / 32768.0F;
complexSignal[i] = new Complex(temp,0.0);
}
y = FFT.fft(complexSignal);
mMaxFFTSample = 0.0;
int mPeakPos = 0;
for(int i = 0; i < (mNumberOfFFTPoints/2); i++)
{
absSignal[i] = Math.sqrt(Math.pow(y[i].re(), 2) + Math.pow(y[i].im(), 2));
if(absSignal[i] > mMaxFFTSample)
{
mMaxFFTSample = absSignal[i];
mPeakPos = i;
}
}
return absSignal;
}
public static void main(String[] args) throws UnsupportedAudioFileException, IOException {
File file = new File(FILENAME);
AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(file);
AudioFormat format = audioInputStream.getFormat();
long frames = audioInputStream.getFrameLength();
final double durationInSeconds = (frames+0.0) / format.getFrameRate();
try {
convert();
for(int i = 0; i < endResult.length; i++) {
System.out.println(endResult[i]);
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
我如何endResult[i]
随时间而不是立即打印出字节数组()的值?
每当您打印出一个值时,请执行以下操作:
Thread.sleep(100);
在打印下一个值之前要等待100毫秒(0.1秒)。这当然是可调的。
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