重新定义；先前的定义是“数据变量”

好吧，我要失去理智了。我应该为课堂编写一个程序，该程序确定您输入的年份（代表day年）的天数，而且我感觉自己不知道自己在做什么。在压力水平进一步提高之前，我将获得任何帮助，我将不胜感激。在甚至无法测试我的程序之前我遇到的最终错误（我怀疑这是行得通的）是：

error C2365: 'leap' : redefinition; previous definition was 'data variable'

和

error C2365: 'count' : redefinition; previous definition was 'data variable'

源代码：

#include <stdio.h>

int main(void){

    int d, m, y, x, day, leap, count;


    //Input values for date
    printf("\n Input the Day: ");
    scanf_s("%f", &d);

    printf("\n Input the Month: ");
    scanf_s("%f", &m);

    printf("\n Input the Year: ");
    scanf_s("%f", &y);
    //End input

    int count(int m, int day);

    int leap(int y, int x);



    if (x == 1){
            printf("\nThe day of the year is %f", day + 1);
    }
    else{
            printf("\nThe day of the year is %f", day);
    }

    system("pause");
    return(0);
}


//Count the number of days
int count(int m, int day, int d){
    if (m == 1){
        day = d;
    }
    if (m == 2){
        day = 31 + d;
    }
    if (m == 3){
        day = 59 + d;
    }
    if (m == 4){
        day = 90 + d;
    }
    if (m == 5){
        day = 120 + d;
    }
    if (m == 6){
        day = 151 + d;
    }
    if (m == 7){
        day = 181 + d;
    }
    if (m == 8){
        day = 212 + d;
    }
    if (m == 9){
        day = 243 + d;
    }
    if (m == 10){
        day = 273 + d;
    }
    if (m == 11){
        day = 304 + d;
    }
    if (m == 12){
        day = 334 + d;
    }
    return(day);
}

//Determine if it's a leap year
int leap(int y, int x){
    if (y % 400 == 0){
        x = 1;
    }
    else if (y % 100 == 0){
        x = 0;
    }
    else if (y % 4 == 0){
        x = 1;
    }
    else{
        x = 0;
    }
    return(x);
}