从txt文件读取整数并将其存储到数组中

debugcn 发表于 Dev

亚洲x3

我在从文本文件中仅读取和存储整数时遇到问题。我正在使用一个int数组，所以我想在没有列表的情况下执行此操作。我收到输入不匹配异常，而且我不知道应该如何解决该问题。从中读取的文本文件还包括字符串。

  public static Integer[] readFileReturnIntegers(String filename) {
     Integer[] array = new Integer[1000];
     int i = 0;
    //connect to the file
     File file = new File(filename);
     Scanner inputFile = null;
     try {
        inputFile = new Scanner(file);
     } 
     //If file not found-error message
        catch (FileNotFoundException Exception) {
           System.out.println("File not found!");
        }
    //if connected, read file
     if(inputFile != null){         
        System.out.print("number of integers in file \"" 
              + filename + "\" = \n");
        //loop through file for integers and store in array     
        while (inputFile.hasNext()) {
           array[i] = inputFile.nextInt();
           i++;
        }
        inputFile.close();
     }
     return array;
  }

艾略特·新鲜

您可能会使用类似这样的内容（跳过所有非int值），并且应该关闭Scanner！

// if connected, read file
if (inputFile != null) {
  System.out.print("number of integers in file \""
      + filename + "\" = \n");
  // loop through file for integers and store in array
  try {
    while (inputFile.hasNext()) {
      if (inputFile.hasNextInt()) {
        array[i] = inputFile.nextInt();
        i++;
      } else {
        inputFile.next();
      }
    }
  } finally {
    inputFile.close();
  }
  // I think you wanted to print it.
  System.out.println(i);
  for (int v = 0; v < i; v++) {
    System.out.printf("array[%d] = %d\n", v, array[v]);
  }
}

本文收集自互联网，转载请注明来源。

如有侵权，请联系[email protected] 删除。