在二维字符串数组java中搜索字符串

我建议将改编String[][]成CharSequence。然后，您可以自由地使用a进行所有操作，CharSequence这也意味着您可以使用它java.util.regex.Matcher来搜索字符串，而无需实现自己的搜索算法。

例如：

public class Main {
    public static void main(String[] args) {
        String[][] array2d = createArray();

        int charSeqColumn = 0;
        CharSequence charSequnce = new Array2DColumnCharSequnce(array2d, charSeqColumn);

        System.out.println(charSequnce.toString());

        Pattern patttern = Pattern.compile("ext");
        Matcher matcher = patttern.matcher(charSequnce);

        while (matcher.find()) {
            String matchGroup = matcher.group();
            int start = matcher.start();
            int end = matcher.end() - 1;

            String msg = MessageFormat.format("{0} matched at: [{1}] - [{2}]", matchGroup, start, end);
            System.out.println(msg);
        }
    }

    private static String[][] createArray() {
        String[][] array2d = new String[2][10];
        array2d[0][0] = "N";
        array2d[0][1] = "e";
        array2d[0][2] = "x";
        array2d[0][3] = "t";
        array2d[0][4] = " ";
        array2d[0][5] = "N";
        array2d[0][6] = "e";
        array2d[0][7] = "x";
        array2d[0][8] = "t";
        array2d[0][9] = " ";

        array2d[1][0] = "H";
        array2d[1][1] = "e";
        array2d[1][2] = "l";
        array2d[1][3] = "l";
        array2d[1][4] = "o";
        array2d[1][5] = "W";
        array2d[1][6] = "o";
        array2d[1][7] = "r";
        array2d[1][8] = "l";
        array2d[1][9] = "d";
        return array2d;
    }
}

将输出

Next Next 
ext matched at: [1] - [3]
ext matched at: [6] - [8]

我会CharSequence像这样实现适应

class Array2DColumnCharSequnce implements CharSequence {

    private int column;
    private String[][] array2d;
    private int endIndex;
    private int startIndex;

    public Array2DColumnCharSequnce(String[][] array2d, int column) {
        this(array2d, column, 0, array2d[column].length);
        this.array2d = array2d;
        this.column = column;
    }

    public Array2DColumnCharSequnce(String[][] array2d, int column,
            int startIndex, int endIndex) {
        this.array2d = array2d;
        this.column = column;
        this.startIndex = startIndex;
        this.endIndex = endIndex;
    }

    public int length() {
        return endIndex - startIndex;
    }

    public char charAt(int index) {
        String charString = array2d[column][startIndex + index];
        return charString.charAt(0);
    }

    public CharSequence subSequence(int start, int end) {
        Array2DColumnCharSequnce array2dColumnCharSequnce = new Array2DColumnCharSequnce(
                array2d, column, start, end);
        return array2dColumnCharSequnce;
    }

    @Override
    public String toString() {
        StringBuilder sb = new StringBuilder(this);
        return sb.toString();
    }
}

注意：这Array2DColumnCharSequnce只是一个快速实现，它还没有解决异常处理问题，也没有解决当字符串列中有多个char时发生的情况。

为什么要使用CharSequence装饰器

使数组适应CharSequence其他方法的不同之处在于，您使用标准的Java接口，该接口可与许多其他类一起重复使用，因此非常灵活。

一些经常使用的标准Java类，它们将aCharSequence作为参数

• String.contains(CharSequence s)
• String.contentEquals(CharSequence cs)
• String.replace(CharSequence target, CharSequence replacement)
• Appendable.append(CharSequence csq)
• StringBuffer.append(CharSequence s)
• StringBuilder.append(CharSequence s)

在这里查看完整列表。

使用上面的代码并尝试执行此操作，以查看装饰器的柔韧性。

public static void main(String[] args) {
    String[][] array2d = createArray();

    CharSequence charSequnce = new Array2DColumnCharSequnce(array2d, 0);

    boolean contentEquals = "Next Next ".contentEquals(charSequnce);
    System.out.println(contentEquals);

    CharSequence column1CharSequnce = new Array2DColumnCharSequnce(array2d, 1);
    String replaced = "I want to say Next Next ".replace(charSequnce, column1CharSequnce);
    System.out.println(replaced);
}

将输出

true
I want to say HelloWorld

最后，每个人都必须决定他/她想要什么以及适合什么情况。如果我可以免费“几乎”获得它们，我更喜欢可以给我更多选择的实现。