链接列表从函数返回变量

debugcn 发表于 Dev

丹宁顿熊

嗨，我正在为一个大学做项目，但我陷入了困境。我在C ++中使用链表。我必须设置一个名为Book的类，该类具有变量“ title”，“ author”，“ ISBN”和“ availability”。我在主体中使用函数原型和在其他地方调用的函数这样设置它。

//the prototype
list<Book> bookSetUp();
int main()
{
//the variable in main that will have the list
list<Book> bookList;
//the list being populated in function elsewhere so as to not mess up the main
bookList = bookSetUp();
// more stuff in main 
}
//sets up the book vector list by populating it
//title, author, ISBN, availability
list<Book> bookSetUp()
{
//creates a temp vector to pass it back to the actual vector to be used in the main
list<Book> temp;
//The items that populate the list
Book a("A Tale of Two Cities", "Charles Dickens", 1203456, true);
Book b("Lord of the rings", "J.R.R Tolkein", 123456, true);
Book c("Le Petit Prince", "Antoine de Saint-Exupéry", 123457, true);
Book d("And Then There Were None", "Agatha Christie", 123458, true);
Book e("Dream of the Red Chamber","Cao Xueqin",123459, true);
Book f("The Hobbit","J.R.R Tolkein",123467, true);
//pushes the items into the vector
temp.push_back(a);
temp.push_back(b);
temp.push_back(c);
temp.push_back(d);
temp.push_back(e);
temp.push_back(f);

//returns the list
list<Book>::iterator pos;
pos = temp.begin();
while(pos != temp.end())
{
return pos;
if(pos != temp.end())
{
pos++;
}
}
}

我知道我的文件之间的链接非常重要，我只是无法获取“临时”列表来返回值。任何帮助将不胜感激。谢谢

Xiangyan Sun

在C ++中，大多数容器std::list都可以像其他任何原始类型一样进行复制构造或分配。在您的情况下，直接return就足够了。

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