我怎么知道页面实际上是用浏览器打开的，还是从脚本或src =“ xxx”获取的？
<?php
session_start();
if(!isset($_SESSION['count'])){
$_SESSION['count']=0;
}
// I don't want to
// if(open in brower){
$_SESSION['count']++;
// }
?>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$.ajax({
url:'index.php',
type:'GET',
data:{},
success:function(){}
});
</script>
<?php
echo $_SESSION['count'] ; // the result now is 1,3,5,... for every reload
// I want to get the result 1,2,3,4... for every reload , how to check the page is really open in brower? not run in ajax or get ?
?>
此特定示例的一个简单解决方案是将一些数据传递给ajax请求，并检查ISN是否存在以增加会话数。
<?php
session_start();
if(!isset($_SESSION['count'])){
$_SESSION['count']=0;
}
if(!isset($_GET['dontcount'])){
$_SESSION['count']++;
}
?>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$.ajax({
url:'index.php',
type:'GET',
data:{'dontcount',1},
success:function(){}
});
</script>
<?php
echo $_SESSION['count'];
?>
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