我有以下字符串，我想根据spilts字符串中的最后一个字母进行字符串处理，例如考虑
String str = '02191204E8DA4459.jpg' how to extract 4459 from str ?
我尝试下面的代码，但是在上面的字符串中，字母并不是完全恒定的，例如，我想在数据库中添加序列化的图像
'02191204E8DA4459.jpg' to '02191204E8DA4465.jpg' i.e 6 images
String sec1 = null, sec2 = null, result = null, initfilename = null;
int lowerlimit, upperlimit;
String realimg1, realimg2;
String str1 = "120550DA121.jpg"; // here DA is constant
String str2 = "120550DA130.jpg"; //
String[] parts1;
String[] parts2;
realimg1 = str1.substring(0, str1.length() - 4); // remove .jpg from image name
realimg2 = str2.substring(0, str2.length() - 4); //
if (realimg1.matches(".*[a-zA-Z]+.*")) { // checking whether imagename has alphabets
parts1 = realimg1.split("(?<=\\D)(?=\\d)|(?<=\\d)(?=\\D)"); // It matches positions between a number and not-a-number (in any order).
parts2 = realimg2.split("(?<=\\D)(?=\\d)|(?<=\\d)(?=\\D)"); // It matches positions between a number and not-a-number (in any order).
sec1 = parts1[0];
sec2 = parts1[1];
result = sec1.concat(sec2);
lowerlimit = Integer.parseInt(parts1[parts1.length - 1]);
upperlimit = Integer.parseInt(parts2[parts2.length - 1]);
for (int j = lowerlimit; j <= upperlimit; j++) {
initfilename = result + j + ".jpg";
System.out.println(initfilename);
}
} else {
for (int j = Integer.parseInt(realimg1); j <= Integer.parseInt(realimg2); j++) {
initfilename = j + ".jpg";
System.out.println(initfilename);
}
}
也许不是最干净的方法，因为它不适用于非数字之前的字符串：
String str = "02191204E8DA4459.jpg";
String lastNumber = str.replaceAll("^.*[^0-9](\\d+).*?$", "$1");
System.out.println(lastNumber);
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我来说两句