我有一个代码,它可以工作,但是没有返回文件的实际名称
Views.py:
def upload_file(request):
getusername = ''
getfirstname = ''
getemail = ''
getpassword = ''
if request.method == 'POST':
getusername = request.POST['username']
getfirstname = request.POST['first_name']
def handle_uploaded_file(f):
destination = open('media/filename', 'wb+')
for chunk in f.chunks(): filename = form.clean_data['file'].name
destination.write(chunk)
destination.close()
getemail = request.POST['email']
form = UploadFileForm(request.POST, request.FILES)
filename = request.FILES['file']
def handle_uploaded_file(f):
destination = open('media/filename', 'wb+')
for chunk in f.chunks():
destination.write(chunk)
destination.close()
在forms.py中
filename = form.clean_data['file'].name
request.FILES['file'].name
在你handle_uploaded_file(f)
那里f.name
来源:https : //docs.djangoproject.com/en/1.6/topics/http/file-uploads/#handling-uploaded-files
您的来源应类似于以下内容:
def upload_file(request):
if request.method == 'POST':
form = YourForm(request.POST, request.FILES)
if form.is_valid():
data = loginForm.cleaned_data
username = data['username']
first_name = data['first_name']
#you can retrieve the filename here
filename = request.FILES['file'].name
handle_uploaded_file(request.FILES['file'])
#...
return HttpResponseRedirect('/success/url/')
else:
form = YourForm()
return render_to_response('your.html', {'form': form})
def handle_uploaded_file(f):
#or here
filename = f.name
#...
with open('some/file/name.txt', 'wb+') as destination:
for chunk in f.chunks():
destination.write(chunk)
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我来说两句