我有一个CALayer带有floatanimAngle属性的子类，标记为@dynamic。我已经实现的方法actionForKey，initWithLayer，needsDisplayForKey和drawInContext为子类。的定义actionForKey如下
- (id<CAAction>)actionForKey:(NString *)event {
if([event isEqualToString:@"animAngle"]) {
return [self animationForKey:event];
}
return [super actionForKey:event];
}
和
- (CABasicAnimation *)animationForKey:(NSString *)key
{
NSString *animValue = [[self presentationLayer] valueForKey:key];// Logs as 0
CABasicAnimation *anim;
if([key isEqualToString:@"animAngle"]) {
anim = [CABasicAnimation animationWithKeyPath:@"transform.rotation.z"];
anim.repeatCount = HUGE_VAL;
anim.autoreverses = YES;
//anim.fromValue = [[self presentationLayer] valueForKey:key]; // setting animation value from layer property as in here does not work.
anim.fromValue = [NSNumber numberWithFloat:0.5f]; // This works
}
anim.timingFunction = [CAMediaTimingFunction functionWithName:kCAMediaTimingFunctionEaseInEaseOut];
anim.duration = 0.11;
return anim;
}
在其他班级：
myCASublayer.animAngle = 0.5f;
以某种方式CABasicAnimation返回的对象将无法正确使用图层的“ animAngle”属性。我在这里可能做错了什么？
CocoaHeads会议：Rob Napier在“动画自定义图层属性”上很好地介绍了自定义动画。
CALayers讨厌画画;）
本文收集自互联网，转载请注明来源。
如有侵权，请联系[email protected] 删除。
我来说两句