sql嵌套连接内部和左连接

卢森堡

嗨,我想使用带有跟踪列表的MySQL过滤日志。

每个日志都属于一台服务器,

每个跟踪都属于一台服务器,并具有0..N个模式

每个模式都属于一个跟踪

我有3张桌子:

logs     : |  id  |      ip     | url     | server_id | ...
tracking : |  id  | server_id   | name    | other fields...
pattern  : |  id  | tracking_id | pattern |

我想计算与特定服务器的跟踪匹配的日志,我的问题是我的查询混淆了有模式和无模式的跟踪。

SQL小提琴:http ://sqlfiddle.com/#!2/f11b1/2

SELECT COUNT(DISTINCT logs.ip), tr.name
FROM `logs`
INNER JOIN `trackings` as tr ON 
        ( tr.server_id = logs.server_id )
        AND -- OTHER conditions between log and tracking
    LEFT JOIN `patterns` as pt ON 
        ( pt.tracking_id = tr.id )
        AND (logs.url LIKE pt.pattern )
GROUP BY tr.id

我的问题是在第二次联接上,如果我使用INNER JOIN patterns as pt ON我会得到正确的结果,但仅在具有某些模式的跟踪上,如果我使用LEFT JOIN patterns as pt ON我会得到所有跟踪,但计数错误(我得到的结果SELECT COUNT(DISTINCT logs.ip) FROM logs

编辑我可以在跟踪字段中获得正确的结果,该字段指示跟踪是否具有模式和UNION:

(
SELECT COUNT(DISTINCT lg.ip), tr.name
FROM `logs` as lg
INNER JOIN `trackings` as tr ON 
        ( tr.server_id = lg.server_id )
        AND (tr.hasPatterns = 1)
        AND -- Other conditions
    INNER JOIN `patterns` as pt ON 
        ( pt.tracking_id = tr.id )
        AND (lg.url LIKE pt.pattern )
WHERE
GROUP BY tr.id
)
UNION
(
SELECT COUNT(DISTINCT lg.ip), tr.name
FROM `logs` as lg
INNER JOIN `trackings` as tr ON 
        ( tr.server_id = lg.server_id )
        AND (tr.hasPatterns = 0)
WHERE
GROUP BY tr.id, lg.date
)

但我想有一种方法可以不使用Union ...

戈登·利诺夫(Gordon Linoff)

您可以在其中放一个条件count,所以我认为以下内容可以满足您的需求:

SELECT COUNT(DISTINCT (case when tr.hasPatterns = 1 and pt.tracking_id is not null
                            then lg.ip
                            when tr.hasPatterns = 0
                            then lg.ip
                       end)), tr.name
FROM `logs` as lg
INNER JOIN `trackings` as tr ON 
        ( tr.server_id = lg.server_id )
        AND -- Other conditions
    LEFT JOIN `patterns` as pt ON 
        ( pt.tracking_id = tr.id )
        AND (lg.url LIKE pt.pattern )
WHERE
GROUP BY tr.id

编辑:

这将返回您想要的:

SELECT COUNT(DISTINCT (case when tr.size = 0 and pt.tracking_id is not null
                            then lg.ip
                            when tr.size > 0 and lg.size > tr.size
                            then lg.ip
                       end)), tr.name
FROM `logs` as lg
INNER JOIN `trackings` as tr ON 
        ( tr.server_id = lg.server_id )
    LEFT JOIN `patterns` as pt ON 
        ( pt.tracking_id = tr.id )
        AND (lg.url LIKE pt.pattern )
GROUP BY tr.id;

您的SQL Fiddle具有lg.size > tr.size原始条件中没有的其他条件

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