我正在获取如下数据，我想在names= app,app1,app2不循环的情况下获取数据。如何在不循环的情况下实现这一目标？
(
{
date = "12/12/12";
name = app;
},
{
date = "11/02/12";
name = app1;
},
{
date = "14/05/12";
name = app2;
}
)
是的。可以这样尝试。这里不需要采取任何循环的概念，这在有大数据时非常有用。
NSString *str=[[array1 valueForKeyPath:@"name"] componentsJoinedByString:@","];
NSLog(@"desired string:%@",str);
NSMutableDictionary *dict = [[NSMutableDictionary alloc]init];
[dict setObject:@"app" forKey:@"name"];
NSMutableDictionary *dict1 = [[NSMutableDictionary alloc]init];
[dict1 setObject:@"app1" forKey:@"name"];
NSMutableDictionary *dict2 = [[NSMutableDictionary alloc]init];
[dict2 setObject:@"app2" forKey:@"name"];
NSArray *array1 = [[NSArray alloc]initWithObjects:dict,dict1,dict2, nil];
NSString *str=[[array1 valueForKeyPath:@"name"] componentsJoinedByString:@","];
NSLog(@"desired string:%@",str);
O/P:- app,app1,app2
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我来说两句