我编写了一个程序，提示用户猜测1-10之间的数字（我已编程为产生随机数），如果用户成功猜到的数字与其生成的随机数相同，则会打印“祝贺”，否则会提示用户再试一次。但我想在一段时间后（例如Game Over）阻止用户回答。但是提示不断出现，我尝试在while循环中使用break，但它不起作用，我还尝试使用exit函数，该函数实际上停止了程序的运行，但在回答2次后就停止了运行，这不是我的意思想。
#include <iostream>
#include <cmath>
#include <cstdlib>
#include <ctime>
using namespace std;
int main() {
int a,b,c,d,e,f;
// generate a random number, prompt the user for any number if the users guess is in line with the random number generated the user wins else try again
//generate a random number between 1 - 10 store it in a variable
cout << "Random Number Generator \n \n";
srand(time(0));
for(int i = 1; i == 1; i++){
a = 1+(rand() % 10);
cout << a << endl;
}
//prompt the user for numbers ranging from 1 - 10
cout << "type in a number from (1 - 10)\n";
cin >> b;
c++;
//check if the number is the same as the random number
//this checks to see if the user gets the question, else it continues running till he gets it
while(a != b){
cout << "You're incorrect!\n";
cout << "type in a number from (1 - 10)\n";
cin >> b;
while(b <= 3){
exit(3);
}
}
//print result
if(a == b){
cout << "congratulations";
}
return 0;
}
我该如何进行这项工作？
您可以计算用户回答的次数，并在用户执行了所需次数后停止。
//prompt the user for numbers ranging from 1 - 10
cout << "type in a number from (1 - 10)\n";
cin >> b;
int answer_count = 1; // variable to count answers (there is already 1 answer here)
const int max_attempts = 10; // number of attempts the user has
//check if the number is the same has the random number
//this checks to see if the user gets the question, else it continues running till he gets it
while(a != b){
cout << "You're incorrect!\n";
cout << "type in a number from (1 - 10)\n";
cin >> b;
answer_count++; // count this new answer
if (answer_count >= max_attempts){ // check if the count reached the "certain amount of time"
break; // exit from this loop
}
}
或者，您也可以给用户一定的时间进行猜测。例如10秒。这可以使用C ++chrono库轻松实现：
#include <chrono>
#include <iostream>
#include <random>
int main(int argc, char **argv)
{
const int max_time = 10; // seconds
const int min_secret = 1;
const int max_secret = 10;
// This generates a random number between min_secret and max_secret using the STL random library
std::random_device r;
std::default_random_engine e(r());
std::uniform_int_distribution<int> uniform_dist(min_secret, max_secret);
int secret = uniform_dist(e);
auto start = std::chrono::system_clock::now();
int guess;
do {
std::cout << "Type a number from (1 - 10)\n";
std::cin >> guess;
if (guess == secret)
break;
std::cout << "Your guess is incorrect!\n";
// See if the time elapsed since the start is within max_time
auto now = std::chrono::system_clock::now();
auto elapsed_time = std::chrono::duration_cast<std::chrono::seconds>(now - start);
if (elapsed_time.count() > max_time) {
std::cout << "You ran out of time.\n";
exit(0);
} else {
std::cout << "You still have " << max_time - elapsed_time.count() << " seconds left\n";
}
} while (guess != secret);
std::cout << "Your guess was correct, congratulations!";
}
请注意，仅在用户尝试猜测之后才执行时间检查，因此，如果时间限制为10秒，并且用户等待30秒键入内容，则该时间检查仍将允许。要在C定时器完全杀死++程序，你可以使用thread库产卵第二个线程来处理所经过的时间，甚至使用中断根据方案（见https://stackoverflow.com/a/4001261/15284149为计时器示例）。
另外，请注意，用户输入没有被清除，并且如果用户写了数字以外的任何内容，则您的程序将具有未定义的行为。
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