PHP-如何在此条件语句中比较日期/持续时间

sinesine 发表于 Dev

恩格莱斯拉

我有一些代码，允许用户输入“第一次考试”的日期，将该日期与今天的日期进行比较，如果这两个日期之间的差额是一定量，则显示警告/通知（因为其余的考试必须是在参加第一次考试的18个月内完成）。我在解决如何比较条件语句中的日期/日期之间的差异时遇到了麻烦-换句话说，如何将其$difference与“ 18个月”或“ 2个月”进行比较，等等。正确的方向，将不胜感激。

代码：

<?php

// Set first exam date
$firstexamdate = "2015-08-20";

// Work out date that is 18 months from first exam date
$add_18_months = strtotime($firstexamdate . ' + 18 months');
$eighteen_months_time = date('Y-m-d',$add_18_months);

// Check
echo "Date of first exam: " . $firstexamdate . "<br>";
echo "18 months from this date: " . $eighteen_months_time . "<br>";

// Work out diff between cut-off date and today
$today = date('Y-m-d');
$date1 = new DateTime($eighteen_months_time);
$date2 = new DateTime($today);
$difference = $date1->diff($date2);

// Display
echo "Difference/time remaining: " . $difference->y . " years, " . $difference->m . " months, " . $difference->d . " days " . "<br";

// BELOW CODE NOT WORKING

// Display $difference as string
echo $difference->format('Y-m-d');

// Output correct warning colour
if ($difference <=  /* 18 months */ and >= /* 6 months */ {
    echo "Green warning: At least 6 months left.";
} elseif ($difference  <=  /* 5 months */ and >= /* 2 months */ {
    echo "Orange warning: Less than 5 months left.";
} elseif ($difference <=  /* 1 months */ and >= /* 0 months */ {
    echo "Red warning: Less than one month left.";
}

?>

北斋

您可以使用$ difference对象的days属性：

if ($difference->days <=  (18 * 30) && $difference->days >= (6 * 30) {
    echo "Green warning: At least 6 months left.";
}

关于Php文档中的财产日：

如果DateInterval对象是由DateTime :: diff（）创建的，则这是开始日期和结束日期之间的总天数。否则，天将为假。

http://php.net/manual/zh/class.dateinterval.php

编辑

如果您确切需要6个月和18个月，则可以使用以下方法：

$targetDate = new DateTime('20170529'); //here your target date;
$now = new DateTime(); //by default today;
$min = clone $targetDate;
$min->add(new DateInterval('P6M'));
$max = clone $targetDate;
$max->add(new DateInterval('P18M'));
if($now >= $min && $now <= $max){
// your code here
}

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