如何获取与流中的条件匹配的第一个元素？我已经尝试过了，但是没有用
this.stops.stream().filter(Stop s-> s.getStation().getName().equals(name));
该条件不起作用，在除Stop之外的其他类中调用filter方法。
public class Train {
private final String name;
private final SortedSet<Stop> stops;
public Train(String name) {
this.name = name;
this.stops = new TreeSet<Stop>();
}
public void addStop(Stop stop) {
this.stops.add(stop);
}
public Stop getFirstStation() {
return this.getStops().first();
}
public Stop getLastStation() {
return this.getStops().last();
}
public SortedSet<Stop> getStops() {
return stops;
}
public SortedSet<Stop> getStopsAfter(String name) {
// return this.stops.subSet(, toElement);
return null;
}
}
import java.util.ArrayList;
import java.util.List;
public class Station {
private final String name;
private final List<Stop> stops;
public Station(String name) {
this.name = name;
this.stops = new ArrayList<Stop>();
}
public String getName() {
return name;
}
}
这可能是您要寻找的：
yourStream
.filter(/* your criteria */)
.findFirst()
.get();
一个例子：
public static void main(String[] args) {
class Stop {
private final String stationName;
private final int passengerCount;
Stop(final String stationName, final int passengerCount) {
this.stationName = stationName;
this.passengerCount = passengerCount;
}
}
List<Stop> stops = new LinkedList<>();
stops.add(new Stop("Station1", 250));
stops.add(new Stop("Station2", 275));
stops.add(new Stop("Station3", 390));
stops.add(new Stop("Station2", 210));
stops.add(new Stop("Station1", 190));
Stop firstStopAtStation1 = stops.stream()
.filter(e -> e.stationName.equals("Station1"))
.findFirst()
.get();
System.out.printf("At the first stop at Station1 there were %d passengers in the train.", firstStopAtStation1.passengerCount);
}
输出为：
At the first stop at Station1 there were 250 passengers in the train.
本文收集自互联网，转载请注明来源。
如有侵权，请联系[email protected] 删除。
我来说两句