带有按键的键盘按键检测

debugcn 发表于 Dev

g0dst3r

from pynput import keyboard 

def on_press(key): 
    print('Key %s pressed' % key) 

def on_release(key): 
    print('Key %s released' %key) 

with keyboard.Listener( on_press=on_press, on_release=on_release) as listener: 
    listener.join()

如果我持续按下F1按钮并释放，它会说

Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 pressed
Key Key.f1 released

如果我一直按下F1按钮并松开，我希望它像下面那样工作

Key Key.f1 pressed
Key Key.f1 released

请帮我：）

国家整合

pressed = False

def on_press(key): 
    global pressed
    if not pressed and key == keyboard.Key.f1: # only if key is not held
        print('Key %s pressed' % key) 
        pressed = True # key is held

def on_release(key):
    global pressed 
    if key == keyboard.Key.f1:
        print('Key %s released' %key) 
        pressed = False # key is released

代码是很容易解释的，您只需提供一个布尔值pressed，即每当您按下该F1键时，True以及每次松开它时，它就是False。如果press是False，则只需忽略on_press“信号”。

如果要使用每个键来实现此目的，则必须将每个键的状态存储在字典中（或作为类似的对象）。

pressed = {}

def on_press(key): 
    if key not in pressed: # Key was never pressed before
        pressed[key] = False
    
    if not pressed[key]: # Same logic
        pressed[key] = True
        print('Key %s pressed' % key) 

def on_release(key):  # Same logic
    pressed[key] = False
    print('Key %s released' %key)

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