我有一个纵向数据
ID<-c(1,1,1,2,2,2,2,3,3,4,4,4)
time<-c(0,12,36,0,7,23,68,0,23,0,32,45)
Age<-rnorm(12,45,9)
Sexe<-c("F","F","F","M","M","M","M","M","M","F","F","F")
biology1<-rnorm(12,12,3)
biology2<-rnorm (12,100,20)
biology3<-rnorm(12,45,9)
biology4<-rnorm(12,20,2)
Death<-c(0,0,1,0,0,0,0,0,0,0,0,1)
data<-data.frame(ID,time,Age,Sexe,biology1,biology2,biology3,biology4,Death)
我想计算每个数值变量（生物学1，生物学2，生物学3，生物学4）和每个个体的斜率（从开始到结束）。主要是用于计算每个变量的斜率而无需为每个变量重新输入新代码的函数。我不知道该怎么做。
这是一个data.table选项lm
dt[,
lapply(
.SD,
function(x) coef(lm(x ~ time, data = cbind(x, dt[, "time"])))["time"]
), ID,
.SDcols = patterns("^biology")
]
结果如下
ID biology1 biology2 biology3 biology4
1: 1 0.07223152 0.07187708 -2.960618e-02 0.022861337
2: 2 -0.05728224 0.13207814 -2.349493e-01 -0.018541982
3: 3 -0.03925044 -0.63219541 -3.166489e-05 -0.009484951
4: 4 -0.01801599 0.04758699 -6.547484e-03 -0.004253647
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