我正在尝试制作可重用的输入组件。当数据输入时,我想在使用可重用输入组件的地方处理这些输入数据。没有通过作为道具。我遇到错误,Uncaught TypeError: Cannot read property 'value' of undefined
有人可以给我关于如何在这种情况下处理数据的任何想法吗?
InputFieldWithImage.js
import React, {useState} from "react";
import { Form, FormGroup, Input } from 'reactstrap';
function InputFieldWithImage(props) {
const [inputType] = useState(props.type)
const [inputValue, setInputValue] = useState('')
function handleChange(event){
console.log("Input.js");
console.log(inputValue);
setInputValue(event.target.value);
if(props.onChange) props.onChange(inputValue)
}
return (
<>
<Input type={inputType} value={inputValue} name="input-form" onChange={handleChange} class="inputclass"/>
</>
);
}
export default InputFieldWithImage;
AddTicket.js
import { Row, Col } from 'reactstrap';
import { Form, FormGroup, Input } from 'reactstrap';
import ActionButton from './../../components/ButtonComponent';
import InputFieldWithImage from './../../components/InputField/InputFieldWithImage'
import { render } from 'react-dom';
import ReactQuill from 'react-quill';
const AddTicket = (props) => {
const [assignee, setAssignee] = useState('');
const handleSubmit = (evt) => {
evt.preventDefault();
console.log('Assignee:' + assignee);
props.handleClose();
};
const test = () => {
console.log("text");
console.log('Assignee:' + assignee);
};
return (
<div className="popup-box">
<div className="box">
{/* <span className="close-icon" onClick={props.handleClose}>
x
</span> */}
<Form onSubmit={handleSubmit} style={{paddingLeft:30,paddingTop:50}}>
<Row style={{ paddingBottom: 50 }}>
<Col sm={11} xs={11} md={11}>
<h1>Add new ticket </h1>
</Col>
<Col onClick={props.handleClose} m={1} xs={1} md={1}>
<h1 className="close-icon">X </h1>
</Col>
</Row>
<FormGroup>
<Row style={{ marginBottom: '25px' }}>
<Col sm={2}>
<h4>Assignee</h4>
</Col>
<Col sm={2}>
<InputFieldWithImage value={assignee} onChange={(e) => setAssignee(e.target.value)} />
</Col>
</Row>
</FormGroup>
<Row>
<Col sm={2}></Col>
<Col>
<ActionButton text="Send" />
</Col>
</Row>
</Form>
</div>
</div>
);
};
export default AddTicket;
您需要通过event
而不是inputValue
。由于存在input.target.value
。这就是为什么它给出错误
function handleChange(event) {
console.log("Input.js");
console.log(inputValue);
setInputValue(event.target.value);
if (props.onChange) props.onChange(event);
}
这是演示:https : //codesandbox.io/s/hidden-tree-vr834?file=/ src/ App.js
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我来说两句